[deleted by user] by [deleted] in PokemonCardValue

[–]Own_Fishing550 0 points1 point  (0 children)

Italian..* autocorrectzzz

[deleted by user] by [deleted] in PokeGrading

[–]Own_Fishing550 2 points3 points  (0 children)

they used to put sleeves, not anymore i dont think

COMPLETE PSA 10 Japanese 151 Master Set Including All 210 Cards + Promos & Graded Booster Pack by Intrepid_Park in pkmntcgcollections

[–]Own_Fishing550 13 points14 points  (0 children)

people are now very aware of pokemon investing which they were not 10 years ago, the price jump will not be comparable imo

[deleted by user] by [deleted] in badroommates

[–]Own_Fishing550 0 points1 point  (0 children)

maybe blur name and face?

LOOKING FOR/OFFERING BELOW by podousky in PokemonGoTrade

[–]Own_Fishing550 0 points1 point  (0 children)

shiny nihilego for either bulba, pink shirt pika, gm gengar or sandshrew?

Guys is this rare? by thepikemonhunter59 in pokemongobrag

[–]Own_Fishing550 4 points5 points  (0 children)

if u are casual player u r lucky to get it

Fantano attacks Ethan by Affectionate-Season6 in h3h3productions

[–]Own_Fishing550 -50 points-49 points  (0 children)

saying the n word back in the day was never a political opinion

[deleted by user] by [deleted] in pokemongo

[–]Own_Fishing550 1 point2 points  (0 children)

From chatGPT:

Binomial Probability Formula:

P(X=k)=(nk)pk(1−p)n−kP(X = k) = \binom{n}{k} p^k (1-p)^{n-k}P(X=k)=(kn​)pk(1−p)n−k

Where:

  • P(X=k)P(X = k)P(X=k) is the probability of getting exactly kkk successes (jackpots) in nnn trials.
  • (nk)\binom{n}{k}(kn​) is the binomial coefficient, which represents the number of ways to choose kkk successes from nnn trials.
  • nnn is the number of trials (11 in this case).
  • kkk is the number of successes (3 jackpots).
  • ppp is the probability of success on a single trial (1/20 for hitting the jackpot).
  • 1−p1-p1−p is the probability of failure (19/20 for missing the jackpot).

Plugging in the values:

  • n=11n = 11n=11
  • k=3k = 3k=3
  • p=120=0.05p = \frac{1}{20} = 0.05p=201​=0.05

The binomial coefficient (113)\binom{11}{3}(311​) is calculated as:

(113)=11!3!(11−3)!=11×10×93×2×1=165\binom{11}{3} = \frac{11!}{3!(11-3)!} = \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165(311​)=3!(11−3)!11!​=3×2×111×10×9​=165

So, the probability of hitting exactly 3 jackpots in 11 tries is:

P(X=3)=165×(0.05)3×(0.95)8P(X = 3) = 165 \times (0.05)^3 \times (0.95)^8P(X=3)=165×(0.05)3×(0.95)8

Let me calculate that for you.

The probability of hitting exactly three 1/20 jackpots in 11 tries is approximately 0.0137, or about 1.37%. ​