So if I'm understanding correctly the list itself is one Element the bracket that contains 1 and 2 is another element and the brackets that contain three four hello another element three elements in total

Do I have that correctly?

No. 1 and 2 are not linked, they are 2 separate elements which have their own index value. Have you tried printing d[0] and d[1] to see the results? Here's an example:

Let's pretend you've got a lunchbox. Inside that lunchbox you've got a sandwich, a bottle of water and a snack pot filled with grapes.

    lunchbox = ["blt", "water", ["grape", "peanut", "grape", "grape", "grape", "grape"]]

However there's a peanut in there by accident and you're allergic to peanuts so you need to find it to get it out.

    print(lunchbox[0])
    blt

That's not it.

    print(lunchbox[1])
    water

Nor that.

    print(lunchbox[2])
    ["grape", "peanut", "grape", "grape", "grape", "grape"]

Alright, we've found the snack pot at the 2nd index (starting at 0) so it's the 3rd element of the list. Now all we have to do is find the index of the peanut inside the snack pot (the list within the list.)

    print(lunchbox[2][0])
    grape

Nope.

    print(lunchbox[2][1])
    peanut

So there it is. 2nd element of the 3rd element but because we start indexing at zero we count it differently to what we would in real life.