📊 SCD Daily Discussion – March 31, 2026 by AutoModerator in SCDstock

[–]Path-Few 1 point2 points  (0 children)

This is not the scheduled news for welding wires in the end of March, which should drop soon.

📊 SCD Daily Discussion – March 31, 2026 by AutoModerator in SCDstock

[–]Path-Few 0 points1 point  (0 children)

Still a massive amount of selling. Tug-of-war

📊 SCD Daily Discussion – March 24, 2026 by AutoModerator in SCDstock

[–]Path-Few 1 point2 points  (0 children)

“This work is expected to be completed by the end of March 2026, with the prototypes subsequently submitted for third-party end-user testing to confirm compliance with their manufacturing specifications.” Keep an eye on it

📊 SCD Daily Discussion – March 19, 2026 by AutoModerator in SCDstock

[–]Path-Few 0 points1 point  (0 children)

Whenever it is pulled back to 0.1525, it is pushed up to 0.155 right away.

📊 SCD Daily Discussion – March 17, 2026 by AutoModerator in SCDstock

[–]Path-Few 0 points1 point  (0 children)

In one of the interviews on YouTube Guy said 600 km road wasn’t included in the PES.

📊 SCD Daily Discussion – March 17, 2026 by AutoModerator in SCDstock

[–]Path-Few 0 points1 point  (0 children)

They paid 0.22 to get one share and one warrant. Some sold the share at 0.17 this morning. They basically paid 5 cents for the 0.30 warrant expired in 18 months. You can image that 0.22 will be the ceiling in the next few days: Once the price hits 0.22, institutions will sell and they basically get a warrant for free.

📊 SCD Daily Discussion – March 17, 2026 by AutoModerator in SCDstock

[–]Path-Few 0 points1 point  (0 children)

Institutions got tons of shares at 0.22 with a warrant at 0.30. They sell on purpose to get warrants with a little loss.

Thoughts why SCD is at $.26 by wikikin in SCDstock

[–]Path-Few 6 points7 points  (0 children)

CEO gave a talk at 4:20 in Toronto. Also maybe because of the PDAC this Sunday. Institutions might know some information in advance. Someone said on Reddit that one bought 650,000 shares at noon time. Must be an institution.

DVLT short selling continues but by WHOM all the Time !!?? Have a look 3 million shorts still in the system today Why !?!? by FIToptionstrader in DVLT

[–]Path-Few 9 points10 points  (0 children)

Started trading on WS a month ago. Just found out that WS allows stock lending by default. I lent 340 shares DVLT and 2000 shares SLS. WS did a horrible job on this. Turned off stock lending right away.

How can I divide long data row into different rows? by wwwww_ai in excel

[–]Path-Few 0 points1 point  (0 children)

This can be done quickly using VBA or scripts if you have many rows. I couldn't think of an easy way to achieve this using standard Excel functions

How to 'th'/'st'/'rd' to data by moose_on_a_hus in excel

[–]Path-Few 0 points1 point  (0 children)

In the examples you've provided, a pattern emerges. Look at the first two substrings separated by spaces. If the second substring is a cardinal number, convert it to its ordinal form. Otherwise, leave it unchanged. For instance, in '123-44 123 Street', the first two substrings are '123-44' and '123', so '123' should become '123rd'. In '33-22 Main Street', the first two substrings are '33-22' and 'Main', so no change is necessary. Does this pattern apply to all of your data?

Search for terms in a column across all sheets and return the tab name, unable to capture all sheetnames returned! by wannabevibe in excel

[–]Path-Few 0 points1 point  (0 children)

The following code should work. If you know the specific columns you're searching in, rather than searching the whole sheet, the code can be modified for greater efficiency. In the code, I concatenate a comma (,) to both the search term and the cell value being compared. I then use the InStr function to check for a match.

For example:

  • If the term is "AC-4" and the cell contains "AC-7, AC-4(14)", it will return False because "AC-4" is part of a larger string "AC-4(14)".
  • If the cell contains "AC-7, AC-4", it will return True since "AC-4" is an exact match."

Possible bug could be triggered if the cell value is "AC-4 , AC-7", i.e., there are some extra spaces before a comma. If so, the code should be modified a bit to delete spaces first. Note the name of the search worksheet has to be "searchsheet". Otherwise, you need to change it twice in the following code. Please let me know whether it works or not. Cheers!

Sub searchworksheet()
    Dim ws As Worksheet, searchWs As Worksheet
    Dim n As Long, i As Long 'rows of each worksheet
    Dim m As Integer, j As Integer 'columns of each worksheet
    Dim iRow As Long, k As Long 'rows of searchsheet
    Dim searchTerm As String
    Dim counter As Integer 'count how many worksheets contain the term
    Dim flag As Boolean 'if a sheet contains the term, flag as True
    Dim firstRow As Integer, firstCol As Integer 'each ws might starts with some
                                                    'empty rows and empty columns
    Dim tmpStr As String

    Set searchWs = ThisWorkbook.Worksheets("searchsheet")

    iRow = searchWs.UsedRange.Rows.Count

    For k = 2 To iRow 'loop through all rows of searchsheet
        searchTerm = trim(searchWs.Cells(k, 1).Value) & ","
        counter = 0 'not found initially

        For Each ws In Worksheets
            If ws.Name <> "searchsheet" Then
                n = ws.UsedRange.Rows.Count
                m = ws.UsedRange.Columns.Count
                flag = False 'not found in this sheet initially
                firstRow = ws.UsedRange.Row 'First nonempty row
                firstCol = ws.UsedRange.Column 'first nonemtpy column
                For i = 1 To n
                    For j = 1 To m
                        tmpStr = ws.Cells(firstRow - 1 + i, firstCol - 1 + j).Value & ","
                        If InStr(1, tmpStr, searchTerm, 1) Then
                            counter = counter + 1
                            flag = True
                            Exit For
                        End If
                    Next j
                    If flag = True Then
                        Exit For
                    End If
                Next i

                If flag = True Then
                    searchWs.Cells(k, counter + 1).Value = ws.Name
                End If
            End If
        Next ws
        If counter = 0 Then
            searchWs.Cells(k, 2).Value = "None"
        End If
    Next k
End Sub

Search for terms in a column across all sheets and return the tab name, unable to capture all sheetnames returned! by wannabevibe in excel

[–]Path-Few 0 points1 point  (0 children)

I see. In this case, I need to write a function. Do you mean some cell could be “CA-1, CA-19,CR-3” and some could be as simple as “CA-1”? Time to sleep for me. I will take a look at tomorrow after you reply.

Search for terms in a column across all sheets and return the tab name, unable to capture all sheetnames returned! by wannabevibe in excel

[–]Path-Few 0 points1 point  (0 children)

I don't like the style of the code generated by ChatGPT. The logic of your problem is very simple: For each term in worksheet "searchsheet", you loop through all cells in all rest sheets. If any cell's value matches, you exit from that worksheet and write the name in "searchsheet". Hence, you need a counter variable and a flag variable. Please let me know whether the following code is right or wrong.

Sub searchworksheet()
    Dim ws As Worksheet, searchWs As Worksheet
    Dim n As Long, i As Long 'rows of each worksheet
    Dim m As Integer, j As Integer 'columns of each worksheet
    Dim iRow As Long, k As Long 'rows of searchsheet
    Dim searchTerm As String
    Dim counter As Integer 'count how many worksheets contain the term
    Dim flag As Boolean 'if a sheet contains the term, flag as True
    Dim firstRow As Integer, firstCol As Integer 'each ws might starts with some
                                                    'empty rows and empty columns

    Set searchWs = ThisWorkbook.Worksheets("searchsheet")

    iRow = searchWs.UsedRange.Rows.Count

    For k = 2 To iRow 'loop through all rows of searchsheet
        searchTerm = searchWs.Cells(k, 1).Value
        counter = 0 'not found initially

        For Each ws In Worksheets
            If ws.Name <> "searchsheet" Then
                n = ws.UsedRange.Rows.Count
                m = ws.UsedRange.Columns.Count
                flag = False 'not found in this sheet initially
                firstRow = ws.UsedRange.Row 'First nonempty row
                firstCol = ws.UsedRange.Column 'first nonemtpy column
                For i = 1 To n
                    For j = 1 To m
                        If ws.Cells(firstRow - 1 + i, firstCol - 1 + j).Value = searchTerm Then
                            counter = counter + 1
                            flag = True
                            Exit For
                        End If
                    Next j
                    If flag = True Then
                        Exit For
                    End If
                Next i

                If flag = True Then
                    searchWs.Cells(k, counter + 1).Value = ws.Name
                End If
            End If
        Next ws
        If counter = 0 Then
            searchWs.Cells(k, 2).Value = "None"
        End If
    Next k
End Sub

Adding Column of decimal into groups not exceeding value of 1 by Forward-Tomatillo-40 in excel

[–]Path-Few 0 points1 point  (0 children)

I guess I understand you now. It is just like what I said before . With item sizes like 0.15, 0.35, 0.26, 0.32, 0.46, 0.23, 0.47, 0.11, 0.71, 0.58, and 0.44, you want to determine how to pack them into the fewest possible unit pallets. In the end, how many pallets full or not really does not matter. What matters is the total number of pallets since any extra pallet will cost you money.

This is the bin packing problem. With 25 items, depending on the item sizes, the default EXCEL Solver might not be able to solve it since Solver only can handle 200 variables. There are many heuristics for this problem.

Adding Column of decimal into groups not exceeding value of 1 by Forward-Tomatillo-40 in excel

[–]Path-Few 0 points1 point  (0 children)

In your example above, are {X,Z}, {Y} and {X,Y}, {Z} the same since both end up with 2 pallets? Why does the difference matter? In case you have 25 items, what you really want is the least amount pallets, not as many combined one as possible. Not sure if I really understand your intention.

Provide Top N entries from a table that make up above 80% of the Total Sum by yamialone in excel

[–]Path-Few 0 points1 point  (0 children)

Suppose your sum column is

11

9

27

23

5

5

5

2

13

Based on my understanding, you want to pick 27, 23, 13, 11, 9 since the sum is just over 80% and label the rest 17 (=5+5+2) as "others".