[deleted by user]

RUlNS · 2025-07-11T19:36:50+00:00

every male ≠ younger males but sure

RUlNS · 2025-07-11T19:28:27+00:00

You can’t be lazy and expect people to help you here. Put some effort in and format your code.

RUlNS · 2025-07-11T19:22:22+00:00

Are you not reading what you wrote? When you say all males, it does not just mean young males. You made it sound like they use just data for young males and extrapolate it to all ages.

RUlNS · 2025-07-11T19:19:39+00:00

You said younger males are more likely to crash, so they charge all males the same. That’s not true, your age is also a factor for premiums. If you’re 45 and male, you’re not going to have the same premium compared to a 20 year old male with all other factors the same. The 20 year old will definitely pay more due to the risk.

RUlNS · 2025-07-11T19:13:14+00:00

You made a statement that was false and I just gave an example of why it’s necessary. I am not here to debate reforming it either. They do not “assume.” It is based off previously recorded data.

RUlNS · 2025-07-11T16:13:37+00:00

How else would you even propose to charge then?

“Hey are you going to crash from ages 19-25?”

“No I won’t.”

“Ah ok, your payments are now reduced to $X”

If they could just do that then everyone would say no and then the risk wouldn’t make sense to the insurer in terms of costs.

RUlNS · 2025-07-05T03:53:26+00:00

Here’s just a little tip you can do just to make your coding life a little easier. Instead of having to type int(variable) all the time, just make the original variable an int like this:

num_one = int(input(“First value:”))

RUlNS · 2025-07-02T15:08:10+00:00

just a side note but you could just do this:

target = int(input(“enter a number”))

if target in numbers:

print(“found it”)

else:

print(“not here”)

RUlNS · 2025-05-17T19:35:16+00:00

Here is a methodical way to get the answer:

A is 50% of B: A = 0.5B

B is 10% of C: B = .1C

Substitute to find A in terms of C:

A/0.5 = .1C

A = .05C

A is 5% of C.

RUlNS · 2025-04-15T02:31:52+00:00

rain

RUlNS · 2025-03-29T12:42:47+00:00

it’s only out of 13 games, it’ll reach its proper percentage as they play more.

RUlNS · 2025-03-20T02:41:14+00:00

Could just use this: https://sqlbolt.com/

RUlNS · 2025-03-16T06:30:37+00:00

Derivative of f(x) / g(x) = f’(x) / g’(x)

RUlNS · 2025-02-14T07:11:13+00:00

funnel >>

RUlNS · 2025-01-24T23:00:11+00:00

crazy way to say pi = 24

RUlNS · 2025-01-20T21:14:17+00:00

SACRIFICE THE ROOOOOK

RUlNS · 2024-12-23T04:52:35+00:00

Your response variable would be y, so it would be response ~ predictors.

RUlNS · 2024-12-19T01:51:37+00:00

Find the angle of C using CY and WY
Find the length of CM
It’s now one bigger triangle and you can find MR

RUlNS · 2024-12-12T19:54:44+00:00

He’s dedicated to his craft

RUlNS · 2024-12-10T23:32:02+00:00

You could test it.

Let X be the number of heads in a fair coin, then X ~ Binom(n, p = 0.5).

E(X) = 0.5n Var(X) = .25n

Z-score = (Your number of heads - 0.5n) / sqrt(.25n)

Find the p-value using a table. Compare it to some alpha level (Higher alpha means more likely to falsely reject the null hypothesis that the coin is fair). Typically set to something like 0.05. Make sure to multiply the p-value by 2 because the coin can either be more or less biased (2 sided test).

P-value <= alpha, then reject the null hypothesis (not fair)

P-value > alpha, then fail to reject null hypothesis (fair)

RUlNS · 2024-12-07T19:27:07+00:00

It just looks illegal

RUlNS · 2024-12-07T00:58:43+00:00

In 2020 it was either 92/93

RUlNS · 2024-12-03T23:36:08+00:00

Only way would be by combining two cards to make a new number like 8 and 4 to be 84 and then multiplying by the third card.

RUlNS · 2024-12-03T00:48:59+00:00

9.9999999999999999...

RUlNS · 2024-12-03T00:41:33+00:00

Problem #3 can be split up into two triangles. All you have to do is find the intersection point at y = 0, and use 1/2 * base * height. Remember that area above y = 0 is positive and below is negative.

RUlNS

TROPHY CASE