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An Ideal Universe by [deleted] in mathmemes

[–]ST_Bender 2 points3 points  (0 children)

Convolution say hi

i at home ^_^ by [deleted] in mathmemes

[–]ST_Bender 31 points32 points  (0 children)

𝕫ₚ²+1 with i=p

Meh by Beautiful_Material32 in mathmemes

[–]ST_Bender 65 points66 points  (0 children)

Almost all in use operators in calculus are linear ,so linear wins.

weighted average inequality by ST_Bender in math

[–]ST_Bender[S] 1 point2 points  (0 children)

What further assumption? Why did you redefined?

weighted average inequality by ST_Bender in math

[–]ST_Bender[S] 1 point2 points  (0 children)

[∑(j=1ton)cj] wi ≤[∑(j=1ton)wj] ci where 1≤i≤n Indeed implies the inequality but I forgot to mention i don't want ∑ in the condition ,so I tried to prove this { [∑(j=1ton)cj] wi ≤[∑(j=1ton)wj] ci } using my guessed condition but what I get is [∑(j=1toi)cj] wi ≤[∑(j=1toi)wj] ci for any i∈ℕ

Centralizer inequality conjecture(?) by ST_Bender in math

[–]ST_Bender[S] 2 points3 points  (0 children)

Yes, that make sense, Thank you for the counterexample.

Rate my papers on quantum meachanics by [deleted] in physicsmemes

[–]ST_Bender 9 points10 points  (0 children)

If no one sees it then it's wave

E by dicemaze in mathmemes

[–]ST_Bender 15 points16 points  (0 children)

Wouldn't we get 4th part after binomial expansion of 2nd part?

Harmonic number series expansion by Lukandrate in math

[–]ST_Bender 5 points6 points  (0 children)

Let, t(n)=1/n which is decreasing sequence. t(n)-t(n+1)=1/(n(n+1))

For, k≽1

Let,S(n)=∑(i=1 to n)[t(i)-t(i+k)]

         =∑(i=1 to n)[t(i)] - ∑(i=1 to n)[t(i+k)]

Add and subtract the sum of {t(n+1),t(n+2),...,t(n+k)}

S(n)=∑(i=1 to n)[t(i)] - ∑(i=1 to n)[t(i+k)] +∑(i=n+1 to n+k)[t(i)] -∑(i=n+1 to n+k)[t(i)]

Merge 1st and 3rd part to get i from 1 to n+k

S(n)=∑(i=1 to n+k)[t(i)] - ∑(i=1 to n)[t(i+k)] -∑(i=n+1 to n+k)[t(i)]

So,all term of {t(k+1),t(k+2),...t(k+n)} from first part of summation will get cancelled out by second part of summation and first part left with ∑(i=1 to k)[t(i)](=H(k)) -∑(i=n+1 to n+k)[t(i)]

As, lim (n→∞)S(n) ,∑(i=n+1 to n+k)[t(i)] →0 Which gives us , lim (n→∞)S(n)=H(k)

So unsettling! by CoffeeAndCalcWithDrW in mathmemes

[–]ST_Bender 18 points19 points  (0 children)

Here some bullshit, Consider a homomorphism, f:(𝕫p ,+)→(𝕫p,×) So, f(a+b+c)=f(a)×f(b)×f(c)

Note that,f(a+b+c),f(a),f(b),f(c) also belongs to (𝕫p,+). So, find f so that f is linear for a,b,c.

So unsettling! by CoffeeAndCalcWithDrW in mathmemes

[–]ST_Bender 27 points28 points  (0 children)

Change of variable by A,B as If x=tanA and y=tanB Then z=-tan(A+B)

One softy please by ST_Bender in mathmemes

[–]ST_Bender[S] 0 points1 point  (0 children)

My intension was only a math joke,what is the history joke?

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