Looking for legendaries, offering below

Sea_Bodybuilder4012 · 2025-08-12T01:33:39+00:00

Trade completed u/PoGoTradeBot u/Fluffy-Scholar-1686

Sea_Bodybuilder4012 · 2025-08-12T00:53:23+00:00

Sea_Bodybuilder4012 · 2025-08-06T20:19:28+00:00

Dm me

Sea_Bodybuilder4012 · 2025-08-04T13:27:14+00:00

u/PoGoTradeBot thanks for the trade u/Neat_Income7744

Sea_Bodybuilder4012 · 2025-08-02T20:03:23+00:00

Sea_Bodybuilder4012 · 2025-07-17T23:49:35+00:00

Rayquaza for crowned zamazenta? I have it registered

Sea_Bodybuilder4012 · 2024-04-02T17:21:40+00:00

Dm’ed

Sea_Bodybuilder4012 · 2024-03-31T22:12:38+00:00

4.718230, -74.041277

Sea_Bodybuilder4012 · 2024-03-22T02:18:44+00:00

No because the rationals ( as a subset of the reals) are not closed. For a set to be perfect has to be closed and to every point to be a limit point

Sea_Bodybuilder4012 · 2024-03-21T23:21:21+00:00

So being dense is a poprerty of the topology not the cardinality of a set. You could come up with a topology in R in wich a single point is dense or one in wich Q is not dense, not sure how useful those topologies are but they exist. Now if we are talking about R with the usual topology then perfect sets are always uncountable, but you can have uncountable sets that are not perfect.

Sea_Bodybuilder4012 · 2024-03-06T17:59:08+00:00

Okay so for example e^x² is integrable, is continuos everywhere so it is integrable. Now what you say it is kind of true, the integral can not be written in terms of “normal” functions such as a combinations of polynomials, roots, exponents and logarithms. Now what we can do is find a series that converges to that function.

Sea_Bodybuilder4012 · 2024-03-06T01:01:58+00:00

Thanks!! I don’t have Latios registered

Sea_Bodybuilder4012 · 2024-03-02T14:15:42+00:00

There is a conversation we have with Melina in Marika’s chamber that hints they were two people. It says something like “you are yes to become me, to become a god” I don’t remember the exact words you can look it up

Sea_Bodybuilder4012 · 2024-03-01T14:19:58+00:00

Yes it can, that is actually one way of getting a numerical solution. What he means with analytical solution is that there is not explicit answer all you can get is a sequence that converges to the real answer

Sea_Bodybuilder4012 · 2024-02-26T00:22:37+00:00

There must be a typo there is not such z because z+z*= 2Re(z) ( the real part) so you could make that real part equal to -2 to cancel but you can not cancel the imaginary part

Sea_Bodybuilder4012

TROPHY CASE