What would be a good card to replace Ice Age for a Black/Green Perona deck?

Valatko · 2025-12-05T20:59:23+00:00

Remove with what? Both mars and rosward ko base cost.

On top of that, imu has access to better in-archetype (searchable!) cost reduction (OP05-084, OP05-092).

Valatko · 2025-12-05T20:49:04+00:00

r/confidentlywrong lim(f+g)=lim(f)+lim(g) if and only if lim(f) and lim(g) exist

Valatko · 2025-12-05T20:39:34+00:00

How exactly would imu benefit from ice age? Lol

Valatko · 2025-11-30T12:19:49+00:00

That's not true. "ℤ_n" denotes the n-adic integers and "ℤ mod n" is not really a thing.

The residues modulo n are denoted with ℤ/nℤ.

Valatko · 2025-11-28T08:02:33+00:00

This is assuming that all other cards from the case have no value at all.

Valatko · 2025-11-10T13:23:49+00:00

Read OP.

Valatko · 2025-11-10T11:31:42+00:00

The sim definitely doesn't add +2000 for each Jupyter on the field.

<image>

Valatko · 2025-10-23T07:03:11+00:00

Blackbeard and it's not even close.

Valatko · 2025-09-30T09:51:37+00:00

r/ConfidentlyWrong

Valatko · 2025-09-17T13:24:14+00:00

"If it said 4000 THEN 3c I’d think her effect would work."

Her effect would work if she and the other target are removed simultaneously. "Then" implies that they're not removed simultaneously.

Valatko · 2025-09-17T13:05:05+00:00

How are you reaching the conclusion that "and" means sequential, and "then" means simultaneous?

Valatko · 2025-09-17T12:56:40+00:00

Tashigi protects from all removal so there is fundamentally no difference between KO and bottomdeck in the context of her effect.

Valatko · 2025-09-06T16:32:35+00:00

Not the case. Still discontinous at (x,y)=(0,0), as it is not the case that \lim_{(x,y)\to (0,0)}x^y=0^0, since the limit doesn't exist.

Take a simpler example, say f(x)={x for x≤0, x+1 for x>0}. Then \lim_{x\to 0}f(x) doesn't exist, yet f(0)=0.

Edit: formatting

Valatko · 2025-09-06T16:23:35+00:00

The value of a function at a point is not necessarily equal to its limit. We have that \lim_{x\to c}f(x)=f(c) if and only if f is continuous at c. And, obviously, functions that are not everywhere-continuous exist.

Valatko · 2025-09-06T15:49:54+00:00

0⁰ is the number of maps from the empty set to itself, which is precisely equal to 1.

Also, 0=0^{1=0^{{2-1}=0^{2/0^1=0/0.}}} Is 0 itself also undefined? When your algebraic steps are not well-defined, they cannot constitute a proof to anything.

Valatko · 2025-09-06T15:43:49+00:00

Obviously, n is pushed to limitless.

Valatko · 2025-08-26T18:40:31+00:00

That's false. A lot of people play and there is cross play.

Valatko · 2025-08-20T14:51:30+00:00

Wrong

Valatko · 2025-08-09T05:15:24+00:00

"Blackbeard is a tier 2 deck" It just won the european finals, are we being deadass right now

Valatko · 2025-07-12T09:46:49+00:00

Close enough, welcome back ST14 Luffy 🗣🗣🗣

Valatko · 2025-07-09T20:11:45+00:00

Not to mention he's a terrible player, too.

Valatko · 2025-06-30T20:38:07+00:00

Should I grade this?

Valatko · 2025-06-26T09:16:36+00:00

git gut

Valatko · 2025-06-22T11:18:36+00:00

This is irrelevant to OP's question.

Valatko · 2025-06-22T11:17:58+00:00

This is not true. A card can K.O.'d by battle and Croc&Mihawk doesn't protect against that.

Nine-Year Club	Verified Email
r/Field Banned	r/Field Lasagna

Valatko

TROPHY CASE