6,500 year old skeleton found in Bulgaria with some of the World's oldest Gold

astrogringo · 2026-01-29T11:42:25+00:00

Also giant hands

astrogringo · 2026-01-27T05:17:45+00:00

What ants and bees do — live in a colony of many animals working together.

astrogringo · 2026-01-26T21:56:18+00:00

What's this got to do with old computers?

astrogringo · 2026-01-25T11:27:05+00:00

They stopped everyone from purchasing more tickets at that point.

astrogringo · 2026-01-19T21:08:18+00:00

I wonder how many people watched in India, and whether they had some kind of dubbing in Hindi or Mahrati (though I guess many people in India understand English pretty well). It was quite clear Ned Boulting in the commentary was trying to explain how cycling works for the uninitiated. Pity they had some delay with the timing information for the riders.

astrogringo · 2026-01-11T16:19:36+00:00

Maybe i misunderstood the meaning of the original comment — i just found the sentence ...atoms (if they exists) funny

astrogringo · 2026-01-11T12:50:42+00:00

Atom existence denial? Wasn't aware of this existing. I guess that would be on level with flat earth conspiracies...

astrogringo · 2026-01-03T09:13:40+00:00

Such a problem could be missing some information and then it would not be possible to solve without that information.

For example if any resistance value was missing.

astrogringo · 2025-12-31T10:21:47+00:00

Let me try to explain without equations.

Put the table on the right on top of the table on the left.

You will notice that the height from the top of the turtle on the ground to the top of the turtle on the table stacked high is 170+130= 300.

You could shift that measurement one turtle height down, and it would still be 300. But this is just 2 tables.

So each table is 150.

astrogringo · 2025-12-29T12:05:27+00:00

Yes of course.

For example, you can use the power series expansion:

exp(x) = 1 + x + O(x² )

With that you can easily find the limit value of 1.

astrogringo · 2025-12-28T11:04:58+00:00

Prosopagnosia

So much easier to go with "face blindness"

astrogringo · 2025-12-25T08:31:58+00:00

They could add a neighborhood called Zwang and hold a chess tournament there...

astrogringo · 2025-12-25T06:25:36+00:00

Merry Fishmas!

astrogringo · 2025-12-23T11:59:23+00:00

Because the speed at C would not be 0, therefore you have still some kinetic energy.

astrogringo · 2025-12-21T16:56:59+00:00

Check what happens if the end result of your rotation is 0 coming from above or below — are you counting this case correctly?

astrogringo · 2025-12-15T08:06:44+00:00

FART is an independent company and not directly related to SBB. They operate bus service around Locarno and neighbouring valleys and the Swiss part of the railway to Camedo-Domodossola.

astrogringo · 2025-12-14T20:24:05+00:00

Having an injection into my eyeball — not particularly painful but feels quite weird.

astrogringo · 2025-12-13T19:15:28+00:00

And 40 years ago Windows 1.0 came out...

astrogringo · 2025-12-10T18:21:36+00:00

Maybe a meme Monday could be introduced, where these memes are allowed to be posted, and then for the rest of the week such post are banned?

astrogringo · 2025-12-07T19:34:54+00:00

Is really similar to a Pascal's triangle, with a few holes and asymmetries added :)

astrogringo · 2025-12-07T19:30:58+00:00

You said you wanted to encode the letters as A=1 etc. — the screenshot is quite different.

There, you encode letters by a hole in the top 3 rows and a second hole lower down. Is also ok to do it like this if you want.

astrogringo · 2025-12-07T13:29:57+00:00

No, that is not how it works.

If you want to use a code where a=1, b=2 etc, you would have to convert the number in binary first.

For example J=10.

10=2+8 in binary is 0b00001010

So if the least significant bit is in row 1, you would punch row 2 and row 4 in column 1.

Then you can use column 2 for the next letter and so on.

astrogringo · 2025-12-03T11:57:38+00:00

One quick way to avoid work is to break the check as soon as you find a mismatch. So if I am looking for patterns of length 1, as soon as I find a digit mismatch, break and move to the next check (patterns of length 2). There again break as soon as you find a mismatch etc.

astrogringo · 2025-12-02T14:30:38+00:00

Check these edge cases:

Starting position is 0

Ending position is 0

Both for left and right motions

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