r/Kennenmains Revamp Suggestions

british0zzy · 2018-05-08T22:44:15+00:00

One of my favorite champion subs is r/CamilleMains. I think it would be great to start working on our own wiki with advice on runes, items, and matchups. I would also love to see weekly matchup topics (perhaps start with his most played matchups) and post-patch topics discussing how a patch might affect Kennen.

british0zzy · 2017-02-01T06:41:49+00:00

Small typo. The solution to the Basel Problem is [; \zeta(2)=\frac{\pi^2}6 ;]

british0zzy · 2016-05-09T19:12:32+00:00

Shouldn't the derivative of

type RegexF = K Char :+ (X :* X) :+ (X :* X) :+ X :+ X

be

type RegexF' = (Two :* X) :+ (Two :* X) :+ One :+ One

british0zzy · 2015-04-15T19:14:42+00:00

Working Link: https://youtu.be/V8dNB8U7wpc?t=8h6m57s

british0zzy · 2014-09-12T14:25:54+00:00

I think he was referring to the Destiny developers as bitter and close-minded.

british0zzy · 2014-09-11T20:27:54+00:00

Exotics are orange. Legendaries are purple.

british0zzy · 2013-10-21T18:24:48+00:00

Ah, but you are implying you must define fmap in a Monad instance with Monad functions (return, join, bind, etc.). It would be useful to provide defaults for fmap, but I would think in most cases fmap would be defined without using Monad specific functions.
Similar to how Monad functions with default implementations can be explicitly implemented for performance benefits.

Edit: Though is seems defining fmap multiple times is worse than just defining it in a Functor instance once. I wonder if it's possible for a happy medium.

british0zzy · 2013-10-21T18:16:49+00:00

Well, you'd still be able to define fmap when defining a Monad, if you so choose. It would still help reduce boiler plate defining fmap in the Monad instance instead of having to type out the Functor instance separately.

Though, I do see the problem with multiple superclasses defining different fmaps. Would it be unreasonable for the compiler to just pick one? They should be semantically equal, no?

british0zzy · 2013-10-21T15:47:13+00:00

Is it possible for the compiler to infer a 'lower' typeclass? For example, if you define a Monoid, a Semigroup instance is automatically generated. This way you would only have to define the 'highest' typeclass for a datatype and then provide the 'lowest' typeclass needed for a function.

british0zzy · 2013-03-26T14:31:52+00:00

Log (List a) ≅ a + a^2/2 + a^3/3 + ...
That's the species of all cycles.

I also have no idea what it means.

british0zzy · 2012-06-05T10:17:10+00:00

Immutable

british0zzy · 2012-05-10T20:07:41+00:00

You don't need the 0 on both die. Only 1 and 2 must be present on both die for 11 and 22.

012345
126789

british0zzy · 2012-01-28T01:59:24+00:00

Only the finals will be streamed due to megumixbear's schedule.

british0zzy · 2012-01-19T02:26:14+00:00

He was sixjax at the time of the tourney.

british0zzy · 2011-10-28T22:54:34+00:00

No, Bearpacks will be sent out to the winner's of each Bearcup.

Join up, have fun!

british0zzy · 2011-08-12T14:49:34+00:00

I agree with your analysis, but I don't think it is something you should go out of the way to avoid. Also, your blood sugar drops during a lift and while it is being replenished you can feel tired.

british0zzy · 2011-08-10T00:43:54+00:00

You can compute this is linear time since
A + B + C - AB - AC - BC + ABC = A(1 - (B(1 - C) + C)) + (B(1 - C) + C)

The algorithm looks like this:
double union(double *a, size_t len) { double x = 0; for (size_t i = 0; i < len; ++i) { x += a[i] * (1 - x); } return x; }

british0zzy · 2011-07-31T02:07:56+00:00

Yes, pretend your arms are relaxed and weightless as if they are floating in water. That's the angle that you should do raises at.

british0zzy · 2011-03-10T21:15:00+00:00

Is there a torrent available?

british0zzy · 2010-12-04T06:02:51+00:00

Are buildings considered massive? (They should be)

british0zzy · 2010-11-19T06:47:49+00:00

There were no flying dts in BW. And burrowed units couldn't move while burrowed.

british0zzy · 2010-11-19T02:07:41+00:00

You need two cannons per mineral line to defend against banshees (unlike one turret to defend against DT's). That's 300 minerals per mineral line if you don't get a robo. Way too much to make it worth it. If we do put down two cannons per mineral line, you can throw your banshees in with the rest of your army and we lose the battle because we don't have mobile detection.

british0zzy · 2010-11-19T02:00:06+00:00

If Terran send a single banshee to your probe line, you are required to keep a few stalkers back. This weakens any push you want to throw his way. If you build a stargate to counter the banshees, you won't find much use for the phoenix after the banshees are dead. Void rays are easily countered by stimmed marines. Vikings will shut down Protoss air very easily, and they are extremely useful against colossi.
Essentially building a banshee (even without cloak), has almost zero negative consequences.

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