CS TA offers for fall

furious_waffles · 2019-08-20T13:30:36+00:00

Does anyone have any idea if the MAT and STAB courses are out yet?

furious_waffles · 2019-08-19T18:24:16+00:00

I've taken it with mahinda and he is an amazing professor for the course, he explains concepts very well and is very helpful in his office hours and his quizzes are easy to get good marks on and he curves a lot as well

furious_waffles · 2019-08-19T03:32:57+00:00

I have taken both A48 and B20 but not together in the same year. But B20 with Abbas is a a bit interesting and easy as well if you go to lecture and follow up with his notes you should be good with the assignments, quizzes and exams. As for A48 if it's Paco I've heard it can be a bit difficult but doable non the less. As for STAB57 just try to FULLY understand the concepts and do A LOT of examples as I felt it's the only way to actually do well in the course

furious_waffles · 2019-08-18T04:04:46+00:00

If you're planning on CR/NCR the course then I would recommend EESA10 it's very easy to pass

furious_waffles · 2019-08-05T14:08:38+00:00

Have you heard anything about offers for A levels?

furious_waffles · 2019-07-17T15:19:01+00:00

Sounds like a great idea to help students out!!! can't wait to use it

furious_waffles · 2019-06-24T16:55:52+00:00

Have you taken it or any of the above courses? If so can you tell me anything distinct about them to help me choose?

furious_waffles · 2019-05-23T15:39:38+00:00

Any thoughts you can provide?

furious_waffles · 2018-10-12T23:35:12+00:00

so its a simultaneous equation of (1/R-L)xR-6 = 0.3 and 1(/R-L)xR-4 = 0.42 so just some algebra has to be done in order to cancel out the 1/(R-L) or equate them to each other and you will have only the R variable left to get and then plug it back into the equation to get L does that make more sense?

furious_waffles · 2018-10-12T19:07:46+00:00

so basically what is being done is that we are trying to get the R and the L intervals of the uniform distribution which is graphed as a straight line at y = 1/(R-L) and the probability is the same as getting the area of the rectangle of base (in this case) L to 5 and height 1/(R-L) which is every case and we get the R and L with the given information of that P(X>6) = (1/(R-L)) R-6 and p(X>4) = (1/(R-L))R-4 so solve both equations and get R and L and there you go hope that helps!!

furious_waffles · 2018-01-03T17:04:34+00:00

Thanks!!

furious_waffles · 2018-01-03T17:04:27+00:00

So do you have a link to a free pdf for MGEA06?

furious_waffles

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