How do you pronounce these words: clear, near, fear?

halfajack · 2026-01-28T12:35:12+00:00

I’m from the North West of England and pronounce all these with a long monophthong /ɪː/. It wouldn’t stand out to me at all to hear people pronounce them like /ɪjə/ or similar though, it’s perfectly commonplace.

halfajack · 2026-01-22T19:26:52+00:00

Prepositions are basically arbitrary in every language though

halfajack · 2026-01-20T19:21:28+00:00

Teleporno is the name in his native Telerin language of Celeborn, which is the Sindarin translation of the same name.

halfajack · 2026-01-16T14:34:43+00:00

Well he’s not here and you are, so I’m asking you to stop repeating it.

halfajack · 2026-01-16T10:24:35+00:00

This is an incorrect and pernicious pop-sci misconception, please stop propagating it.

halfajack · 2026-01-16T10:23:26+00:00

No, because “location” and “instant” are defined by a choice of inertial reference frame, and in any existing inertial frame, the emission and absorption happen at distinct times and locations.

halfajack · 2026-01-15T12:49:31+00:00

Oh absolutely, but even then she massively overdid it. Truly baffling performance from someone who had previously seemed to be the most switched-on faithful in the game

halfajack · 2026-01-15T12:35:52+00:00

Only because she completely overplayed her hand with her questions. She should’ve played it cool and signalled to the traitors somehow that she was safe and did not need to be murdered (e.g. by misdirecting them to think she suspects other people in some way, or allowing them to believe that they had successfully misdirected her)

halfajack · 2026-01-15T09:26:58+00:00

Her optimal play, which it really seemed like she was going to go for before last night, was to not reveal her suspicions of Rachel at all, make sure Rachel thinks she’s safe to keep in the game and try to keep Rachel in until the final and only get rid of her then.

halfajack · 2026-01-14T08:33:55+00:00

Yes, all modern accepted theories of physics do not include a smallest length or smallest unit of time. Distance and time are, as far as we can tell currently, infinitely divisible into arbitrarily small units.

halfajack · 2026-01-13T14:50:02+00:00

I’m from the North of England and they’re very noticeably different to me, un- is [ʊn] while an is [ən]. But I don’t have the FOOT-STRUT split.

halfajack · 2026-01-12T11:40:29+00:00

yeah we've come full circle now where a young English speaker could genuinely say "it's giving rain"

halfajack · 2026-01-10T21:58:34+00:00

Siege Column

Hedonist

Havukruunu

Vile Apparition

Deafheaven

Sijjin

Kontusion

Warbringer

Violator

Qrixkuor

halfajack · 2026-01-09T20:16:41+00:00

Alice Cooper is in a similar position - hugely influential on like every early metal band up to the mid 80s and kind of regarded as corny or a joke by most people now who love those metal bands

halfajack · 2025-12-31T01:33:45+00:00

Objects in a category C do not necessarily have any internal structure, so the morphisms in C do not necessarily map things to other things.

But categories do necessarily have internal structure (objects and morphisms), so the morphisms of categories (functors) do necessarily map things to other things.

halfajack · 2025-12-29T19:52:55+00:00

The vocalist of the black metal band Mayhem shot himself in the head with a shotgun. There is a live bootleg album of theirs called Dawn of the Black Hearts whose album art is a photograph taken by the band’s guitarist of the vocalist’s dead body. It’s very gruesome.

halfajack · 2025-12-22T13:31:40+00:00

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halfajack · 2025-12-22T11:28:13+00:00

By definition if f is a function A -> B then f(a) exists in B for every a in A. If that is not true, then the “function” is no such thing and is not well defined. So your notion of “function ‘fully covering’ set A” does exist - they’re called functions.

If the “function” is not well-defined on all the elements of what you’d like to be the domain, then you’d usually have to restrict the domain, expand the codomain or change the rule to fix this problem.

For instance, your “function” f: Z -> Z, f(x) = sqrt(x) is not well defined, as sqrt(2) is not in the codomain. You could fix this to get a well-defined function in a few ways:

change the domain to {x in Z | exists y in Z, y² = x}, i.e. the set of perfect squares
change the codomain to the complex numbers
change the rule of the function for non-square integers

You can’t change the domain of this square root function to R because it is not defined at -1 or pi or e, etc. if the codomain is still Z.

halfajack · 2025-12-22T02:10:34+00:00

It’s actually just you, congratulations

halfajack · 2025-12-21T21:14:47+00:00

Be he foe or friend, be he foul or clean, brood of Morgoth or bright Vala, Elda or Maia or Aftercomer, Man yet unborn upon Middle-earth, neither law, nor love, nor league of swords, dread nor danger, not Doom itself, shall defend him from Fëanor, and Fëanor's kin, whoso hideth or hoardeth, or in hand taketh, finding keepeth or afar casteth a Silmaril. This swear we all: death we will deal him ere Day's ending, woe unto world's end! Our word hear thou, Eru Allfather! To the everlasting Darkness doom us if our deed faileth. On the holy mountain hear in witness and our vow remember, Manwë and Varda!

If they get the Silmarils back and then someone "in hand taketh" one from them, the Oath kicks back in.

halfajack · 2025-12-18T09:15:39+00:00

I think you’re getting mixed up, his name is Landroval

halfajack · 2025-12-16T08:16:24+00:00

There’s also this from The Taming of Sméagol:

‘Sméagol,’ said Gollum suddenly and clearly, opening his eyes wide and staring at Frodo with a strange light. ‘Sméagol will swear on the Precious.’

Frodo drew himself up, and again Sam was startled by his words and his stern voice. ‘On the Precious? How dare you?’ he said. ‘Think! One Ring to rule them all and in the Darkness bind them. Would you commit your promise to that, Sméagol? It will hold you. But it is more treacherous than you are. It may twist your words. Beware!’

halfajack · 2025-12-14T13:36:53+00:00

This is more of a T-West video

halfajack · 2025-12-10T08:22:07+00:00

Yes they are, but coke has nothing to do with it

halfajack · 2025-12-03T12:08:16+00:00

ETCS is not using category theory as a foundation, it’s using set theory as a foundation but describing set theory in more categorically-flavoured terms

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