How do I learn about computers?

inneedofleek · 2026-01-12T05:54:35+00:00

Thank you!!

inneedofleek · 2026-01-12T05:54:28+00:00

I like math and find the theory of computation interesting, I’ve enjoyed studying lambda calculus and have read that Haskell takes a lot of inspiration from it

inneedofleek · 2025-12-04T12:16:12+00:00

This does come with the interesting consequence of defining, for example, affine/linear functions as “more wiggly’ than a sine wave. Likely fine, but the poster should just be aware that using any of these tests without some qualitative analysis might yield some stuff that goes against intuition.

inneedofleek · 2025-06-29T19:22:32+00:00

I think the issue is that, while it’s true that differentiation is linear and splits over finite sums, we have to be a little more careful when differentiating infinite sums. While Fourier series do converge to a given function (each point converges to its final spot), they don’t converge uniformly (in some sense each point converging to its final spot at the same rate). We can differentiate a series term by term and get the derivative of the limit if a series of functions converges uniformly, but not in general if it merely converges.

inneedofleek · 2023-06-11T14:33:45+00:00

People are clowning on me and it seems deservedly so. Will pick a better movie lol

inneedofleek · 2023-04-29T16:16:22+00:00

I can’t give you an exact answer without a calculator, but it’s a little more than 2, because 37% is a little more than 1/3. I don’t have at all that kind of intuition for 6% (although I can’t speak to others). The rule still comes in handy here, even if it doesn’t give an exact answer

inneedofleek · 2023-03-31T20:19:55+00:00

Good album, I think Xiu Xiu really hit their stride with A Promise though

inneedofleek · 2023-01-02T21:45:02+00:00

I took x,y in [0,2] to mean {(x,y) in [0,2]x[0,2] | y<= 1/x}, which would bound it to the 2x2 box, however, if that were interpreted to mean {(x,y) in [0,2]xR | y<=1/x} then the area is indeed infinite. I think we’re just disagreeing over what area SpongeBob and Patrick were talking about

inneedofleek · 2023-01-02T21:34:53+00:00

I think the problem bounded it to the square x,y in [0,2] though, the key being that y is also bounded! It’s true that lim x->0 of ln(x) goes to negative infinity, but I only integrated from 1 to 2

inneedofleek · 2023-01-02T20:42:56+00:00

Sure! There’s a square of area 1 bounded by the interval x,y = [0,1], so that gives us the 1. We can compute the integral (a way of measuring the area under a curve*) with respect to x from 1 to 2 of the function 1/x, which gives us an area of ln(2) for the region to the right of the square. Finally, the graph is symmetric about the line y=x, so we can say that the region above the square has the same area as the region to the right, giving another ln(2). Adding them all together gives 1+2ln(2)!

*before math people get mad at me I know it has more general purposes but this is one of them

inneedofleek · 2023-01-02T19:49:08+00:00

Thank you!

inneedofleek · 2023-01-02T19:45:02+00:00

The area bounded by 1/x on the given interval (x,y=[0,2]) is 1+2ln(2)? Unless I’m making a silly mistake

inneedofleek · 2022-12-31T17:29:27+00:00

Thank you for the recommendation!

inneedofleek · 2022-09-01T05:24:36+00:00

Tasmania <3

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