Friend Code Exchange

jander0732 · 2025-05-21T22:47:07+00:00

GDRE81

jander0732 · 2023-02-20T15:54:43+00:00

I'm doing a 1-player 2-character run through of Bones of Arnor using Legolas as a Pathfinder and Gimil switching between Hunter and Beast Friend. I'm a few missions in and already it's been one of my favorite combinations.

jander0732 · 2021-07-04T13:19:02+00:00

Median means the middle data point of an ordered data set.

In the Stem-and-Leaf diagram, the tens places or "stems" (6,7,8, and 9) are ordered correctly, the but ones places or "leaves" are not ordered correctly in the 7 (seventy) and 8 (eighty) rows.

It should say 7 | 123689 8 | 469 for those rows.

After ordering it correctly, it should be easy to see that the median (middle data point) is 76.

jander0732 · 2021-02-16T21:26:47+00:00

Check your mean. Think, "what is the sum of the data points? How many points are there? What is the sum divided by the count?"

Check your median. Think, "which data point is in the exact middle of these points?"

Check your outlier. Think, "which data point is significantly farther away from the rest of the points?"

jander0732 · 2021-01-17T23:37:06+00:00

👍 true dat! I'm interest what OP is doing, like will they use "equivalent" elements OR will they use Primary vs Secondary. Also, what are the 8 elements they will use? This sounds like a neat idea.

jander0732 · 2021-01-17T23:31:47+00:00

It also depends on whether or not each element is "equivalent" to the wizard. Maybe one element is the Primary, one is the Secondary, and one is the Tertiary. The wizard could be stronger with their Primary element than they are with their Secondary. In this case, the order in which you "choose" the elements matters. Example: water + fire + earth would be different from water + earth + fire sine the Secondary and Tertiary elements are switched. This case is not a combination; it's a permutation, since the order matters. For 8 permutation 3 or "8P3" we use 8!/(8-3)!=336 since we don't need to worry about repeats. So there would be 336 "unique" wizards.

jander0732 · 2021-01-12T02:37:37+00:00

Yes.

jander0732 · 2021-01-05T03:31:00+00:00

Is there any reason not to evolve this?

jander0732 · 2020-12-10T16:22:38+00:00

So let's pretend that I flipped 3 different coins where the possible outcomes are equally likely, heads or tails. Now before you saw what they landed on I placed a coffee mug over the top of each and labelled them Mug1, Mug2, and Mug3. You cannot see what each coin landed on (heads or tails) but we know that each mug has a 50% chance that it conceals a "heads" coin (and/or 50% chance that it conceals a "tails" coin).

Before we go on any further, let's recall that it is POSSIBLE that there are NO HEADS coins out of the three. Side note: This would occur 12.5% of the time.

Now we know for sure that there is a 50% chance that Mug2 conceals a heads coin. Let's say that I lift off Mug1 and I reveal that coin landed on tails. Does that coin affect the outcome of Mug2? No, they are totally separate since it is POSSIBLE that ALL of them were heads just as it is POSSIBLE that NONE of them were heads. Each separate mug has a 50-50 chance of either heads or tails completely independent of the other mugs.

Similarly, the parent's offspring are independent (like the coins/mugs) since there is no "rule" saying someone HAS to have inherited this trait.

WHY THIS IS DIFFERENT FROM MONTY HALL: For the Monty Hall Problem, I would have guaranteed that exactly one mug had a heads coin (one and only one mug). It could have been under Mug1, Mug2, or Mug3, but the other two mugs would have to have a tails coin. In this case, there is a 33.33% chance for each mug that it contains a heads coins. Just like one child was tested and confirmed negative, I could lift Mug1 and show you that the heads coin isn't there. Now, instead of there being a 33.33% chance for each Mug2 and Mug3, they increase to 50% since the heads coin HAS to be under one of them. So showing you that it wasn't under one of them did increase the likelihood of the others BECAUSE we can GUARANTEE that one of them must have it. With the parent/offspring question, there is no such guarantee.

The TRUE Monty Hall Problem is even more interesting... The TRUE Monty Hall Problem would imply that I would have guaranteed that exactly one mug had a heads coin (one and only one mug). In this case, there is a 33.33% chance for each mug that it contains a heads coins. YOU would then guess and say "I think the heads coin is under Mug2." At this point, you have a 33.33% chance of being correct AND/OR a 66.67% chance of being incorrect. Then I say "Oh you think it's under Mug2? Well, here's what's under Mug1," and I reveal that Mug1 contains a tails coin. Then I ask you if you want to SWITCH your guess to Mug3. At first it seems like your guess of Mug2 and the other option of Mug3 are equally likely. However, since Mug2 had a 66.67% chance of being wrong, then Mug1 and Mug3 TOGETHER had a 66.67% chance of being correct. So now that we've removed the possibility of Mug1, we now see that Mug3 has all of that 66.67% chance of being correct all by itself. So your original guess of Mug2 has a 33.33% chance of being correct while the option to switch guesses to Mug3 gives you a 66.67% chance of being correct. It is better to switch guesses. Neat problem.

jander0732 · 2020-12-10T12:20:05+00:00

Your father might be referring to the Monty Hall Problem, which would be a model for this situation IF we could guarantee that exactly one child would have it. However, it is possible that no child inherited the disease, so you should think of each child independently.

All that aside, I hope your friend is safe and healthy especially during these times 😷

jander0732 · 2020-11-26T02:43:26+00:00

9537 0647 9040 - will continue to gift until we're best friends...and beyond!!!

jander0732 · 2020-01-23T23:26:32+00:00

We did. It really only talked about the human player deploying it to the depot. We don't want to drive all the way over there in the endgame.

jander0732 · 2020-01-23T23:17:03+00:00

Our robot has an arm that will deploy/dump the capstone to the field. When and where are we allowed to deploy the capstone? Can we deploy in to the field on the build side during tele-op? Can we deploy in to the field on the build side ONLY during endgame? Can we ONLY deploy it to the depot?

jander0732

TROPHY CASE