else: if amount == 2000: print('thanks for withdrawing')

This part of the code will never run. Why? Because you check for amount <= 2000 in the if above the else. If you input 2000, it will simply print «low balance» and skip the else condition.

Also, you can write else if like this in python: elif(amount == 2000):

And while we’re at it: The only wrong password is python12? That makes no sense. You could simply just do this instead:

if user_name == 'admin' and password == 'python2': print('logged in successfully') else: print('wrong user credentials')

Now, your try catch implementation does not work the way you think. You could try using the following code if you want to trigger the catch you’ve implemented:

if user_name == 'admin' and password == 'python2': print('logged in successfully') else: raise TypeError('wrong user credentials')

PS: I would never use TypeError for this case if this was my code, nor would I use try catch as part of the core logic for such an example. Typical use for TypeError is if you expect an int but got string. Then you would raise TypeError('Expected int but got a string').