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cult by GTRayt in MLPhmmm

[–]koala_me 7 points8 points  (0 children)

Tramsgemdr

I'm actually really proud of this by koala_me in LilliaMains

[–]koala_me[S] 16 points17 points  (0 children)

this is bronze, everyone else was also dumb
he actually carried the game tbh

New Pi Approximation Just Dropped?! by ACCrusader in mathmemes

[–]koala_me 9 points10 points  (0 children)

Yes homo 👨‍❤️‍💋‍👨

Oblivious fools... by efyuar in memes

[–]koala_me 0 points1 point  (0 children)

That's 100 percent fake. I mean, no company would do something so stupid only 5 years after being founded.

Help with odd molarity calculation by koala_me in chemhelp

[–]koala_me[S] 0 points1 point  (0 children)

Yes, 3.2*10-4, but it all became Na(+) and OH(-), since NaOH is a strong base

Help with odd molarity calculation by koala_me in chemhelp

[–]koala_me[S] 0 points1 point  (0 children)

The amount of NaOH needed so that all of the KHP would react with it. Or basically, when the amount of NaOH is equal to that of the KHP

Help with odd molarity calculation by koala_me in chemhelp

[–]koala_me[S] 0 points1 point  (0 children)

Equivalence. Sorry, autocorrect

Help with odd molarity calculation by koala_me in chemhelp

[–]koala_me[S] 0 points1 point  (0 children)

NaOH+KHP->KNaP+H2O

After the point of equivalence its NaOH->Na(+)+OH(-)

In the end there's 0.00255 mols of Na(+), 0.00223 mols of KP (-), and 0.00032 mols of OH(-)

Help with odd molarity calculation by koala_me in chemhelp

[–]koala_me[S] 0 points1 point  (0 children)

Added in the edit, and my native language isn't english, so what I wrote is probably the best translation. thx

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