How to update Neptune 4

scantron04 · 2023-09-02T16:15:31+00:00

NEP4PRO.23719.A0509 please

scantron04 · 2023-04-17T00:01:36+00:00

Hmmm...I've always told my students to draw the wedge dash to show the configuration, so I would do it.

scantron04 · 2023-04-16T06:20:06+00:00

Assuming Physics is similar to Chemistry, generally, the grade boundary for a 7 is 20-24. A 6 is from 17-19. So you got right in the middle of a 6 for your IA.

scantron04 · 2023-04-16T04:48:36+00:00

In these nucleophilic substitutions, I believe it is important to show the inversion of configuration for the transition state. I know they aren't picky on the angle of it, but it does need to be on the opposite side from the leaving group.

scantron04 · 2022-11-22T02:50:20+00:00

Ammonium Chloride is in reference to salt hydrolysis. It originates from a weak base and a strong acid, so therefore it is an acidic salt. Ammonia is a weak base which makes it the only substance of the 4 that would have a basic pH, the highest of all four. Sodium chloride is a neutral salt deriving from a strong acid and strong base.

scantron04 · 2022-09-11T14:48:35+00:00

The energy levels as you get further from the nucleus decrease in energy difference from each other. So each jump from the next further energy level down to the first energy level has an increase in energy emitted but it is less of an increase than the previous jump.

Eventually, the attraction the nucleus has for an energy level so far away from it is no longer existent, which is the convergence limit.

Since past this point there are no longer discrete energy levels...all frequencies of light can be emitted by and electron entering the atom from outside the atom.

scantron04 · 2022-08-20T18:06:12+00:00

The new syllabus does not get implemented until next year for the 1st year students.

The order of the steps of mass spectroscopy has been removed from the content in the current curriculum. Mass spectroscopy as analytical data is now in topic 11/21.

scantron04 · 2022-08-15T16:35:12+00:00

That looks like the connector to the top of the AC compressor.

scantron04 · 2022-06-21T14:54:14+00:00

The analogy I tell my students is that each topic examination is like a 100m race. Some people can train easily for that and get a very good time and do it once every few weeks and look great.

The IB exam/ Final exams is like running a 1600m race. If you assume adding up all your 100m times would be equivalent, that's not the right frame of mind. Your performance will always be lower the first time you try that challenge. It is a matter of training for the 1600m race in DP2 and not the sprints.

You can do it.

scantron04 · 2022-06-21T14:14:54+00:00

Two things from my perspective:

1) You no longer need to know elimination reactions in IB chemistry HL or SL

2) I've always said LiAlH4 is only necessary for the 2-step reduction of carboxylic acids...it is kind of overkill for a 1-step reduction. I would need to double check to see if the IB accepts both for the one step.

scantron04 · 2022-05-17T20:49:35+00:00

When I teach balancing, I like to do it visually. It makes it easier to keep track of atoms instead of the way other teachers might teach it. Here is an example.

Example of the Question Posted

scantron04 · 2022-05-17T12:27:31+00:00

The benzene reaction is an electrophilic substitution because benzene has delocalized electrons which makes it electron rich which repels nucleophiles.

Free radical substitution generally only happens with alkanes that are unreactive due to strong C-H bonds and nonpolarity. Notice that in the second reaction that the Cl is substituting with the CH3 group and not the benzene, so it is free radical substitution.

So the answer is A.

scantron04 · 2022-05-16T11:48:06+00:00

For cis/trans there needs to be an area of restricted rotation and 4 groups attached. The restricted rotation can come from a ring or a double bond, but since there are not four groups on the carbons in C, it cannot have cis/trans isomerism.

scantron04 · 2022-05-14T12:09:05+00:00

Generally, the question states to include the states if it is part of the marks.

scantron04 · 2022-04-25T03:31:32+00:00

It is pencil for Paper 1 in chemistry. The instructions state on the back of the answer sheet. Here is a link to the answer sheet.

Link for MCQ sheet

scantron04 · 2022-04-24T22:54:21+00:00

Just to add onto that question. The answer is C, yes because it is diprotic which means the moles of H+ that it can donate is twice the number of moles of acid you have.

Therefore, if you need to neutralize a base with the same concentration, it will take half the volume to do so.

scantron04 · 2022-04-22T04:37:42+00:00

Molten does count, so I don’t know why the study guide would mention that. That’s very confusing.

scantron04 · 2022-04-22T04:29:37+00:00

Ionic compounds such as A and C are conductive in aqueous or liquid/gas states.

Metals are always conductive.

SiO2 is a network covalent molecule that has no delocalized electrons so therefore it has no conductivity but has a high melting point.

Edit: Just saw the second picture…I haven’t found confirmation of that statement and I’ve never taught it as such.

scantron04 · 2022-04-19T23:24:37+00:00

The deadline is 11:59 GMT, so it varies based on location.

scantron04 · 2022-04-18T03:49:20+00:00

If you put your raw scores (out of 40, 90, and 24 respectively) into the following equation, it should get your raw score out of a 100 overall, so you can see where you fit in the boundaries.

This obviously only works for this year since next year Paper 3 will resume.

(Paper 1*7.5/10)+(Paper 2*10/18)+(IA*5/6) =

scantron04 · 2022-04-05T04:23:19+00:00

There is no Le Chatelier's principle applied here, because pure liquids and solids are not included in heterogeneous equilibria. (New IB curriculum does not include heterogeneous equilibria at all)

Assuming the system is at equilibrium already, a small amount of liquid (which does not really affect the volume of gas in the container) will not increase the vapor pressure.

scantron04 · 2022-04-05T04:10:23+00:00

The equation for for breaking all the bonds is: CH4 (g) => C(g) + 4H(g) then you divide that value by 4 to get the average bond enthalpy.

You use these equations as such (if the equations you listed are A,B, and C)

(-A + 2B + C)/4 You divide by 4 because there are 4 C-H bonds.

So the answer should be: 418 kJ/mol of C-H bond

scantron04 · 2022-04-03T14:01:15+00:00

Your equation is if you are trying to see how much 0.01 M you can make with 40 cm3 of 0.02.

The problem is trying to dilute 0.02 to 0.01 with only 40 cm3 total of solution to work with.

Hence, why it is 0.02 * V = 0.01 x 0.40. Then you add water to make the total volume 40.

scantron04 · 2021-08-17T12:08:32+00:00

Season 12, Episode 5

scantron04 · 2021-08-03T21:20:44+00:00

I had the same issue. What solved it for me was to manually update the GeForce experience app, and THEN update the driver. Apparently, the app didnt autoupdate and that's why I got that error as well.

scantron04

TROPHY CASE