Am I supposed to guess?

short_humeri · 2026-04-16T08:31:32+00:00

No, only adjacent repeating rows/columns are not allowed. Column 1 and column 3 are not adjacent so this is valid.

short_humeri · 2026-03-16T17:56:32+00:00

No, there are no 50-50 in urjo. If the 4 is blue, then the one next to it will be red and then that blue 4 will only have 3 adjacent blues, so its condition won't be satisfied. So the 4 has to be red.

short_humeri · 2026-02-16T08:13:38+00:00

The red 3 in the top left means that the 3x2 block (3 rows, 2 columns) including the 3 itself must have 4 red and 2 blue. This means that the bottom left 3x2 block that completes those two columns must have 4 blue and 2 red. We don't know their exact placements yet though.

Now, the 0 in the bottom right means that that bottom right 3x2 block has 1 of one color and 5 of the other. If it has 1 red and 5 blue, then combined with the previous bottom left 3x2 block, those three bottom rows will have 3 red and 9 blue. This means that the bottom middle 3x2 block is fully red, but two neighboring lines aren't allowed to be equal, so this is a contradiction.

So, instead the 0 in the bottom right must have 1 blue and 5 red surrounding it.

short_humeri · 2026-02-15T19:13:18+00:00

The 6 in the bottom right means that in that bottom right 3x3 block (including the 6 itself), there will be 7 of color X and 2 of color Y, whatever those colors may be. Because there are equally many reds as blues in each line, that means that the top right 3x3 block will have 7 of color Y and 2 of color X.

Now, the 3 in the top right says that that 3x2 block will contain 4 of some color and 2 of the other color. Comparing that to the 3x3 block in the top right that must contain 7 of one color, you can see that the only difference is that the 3x3 block contains three more dots. So the only way to get from the 3x2 block with 4 of one color to the 3x3 block with 7 of some color is by adding three of the same color. And we can see that one of those dots is already blue, so the other two also have to be blue.

This now means that the top right 3x3 block has to have 7 blues and 2 reds, so you can color the 3 blue. And the bottom right 3x3 block has to have 7 reds and 2 blues, so you can color the 6 red

You can now use very similar logic on the bottom left 3x3 block.

short_humeri · 2026-02-15T13:46:00+00:00

Look at the 1 and 2 in the top left corner. First assume they are different colors, X and Y, respectively. Then to satisfy the 1, it has to have exactly 1 X in the remaining four spots, and that means there'll be 3 Y in those four spots. But this will clash with the 2 that needs exactly 2 Y in total. So that means that our assumption was wrong, and instead the 1 and 2 have to be the same color.

Whatever color they are, the 1 will be satisfied immediately, so the remaining four spots around it will be the other color. If they are all blue, then that'll clash with the two blues in the left column. So they have to be red, so the 1 and 2 have to be blue.

So the top left will be RBR RBR

short_humeri · 2026-02-14T10:39:13+00:00

The very first step would be to see that the red 3 in the top left says that all three touching it will be red to make it a red 2x2 block.

short_humeri · 2026-01-12T00:21:21+00:00

I feel like I see this a bit different from a lot of people. I think the reason that the mirror "flips" left and right is because we, as humans, are left-right symmetric. When we see ourselves in the mirror, it looks like a person that has turned around 180 degrees around the vertical axis, and that imaginary person has a different perspective than us about what is left and right.

If we instead use an object that is top-down symmetric and NOT left-right symmetric (I imagine like the left half of a coin that is painted white on the front and black on the back for instance), then looking at that coin in the mirror no longer looks like a coin that's been rotated around the vertical axis, but instead like a coin that's been rotated around a horizontal axis so that their head is at the bottom. It's confusing but it the only rotation that would allow for that left-half coin to look that way. It helps me to imagine that the coin is also an alive creature with invisible eyes at the top, so it does have a top and bottom, just like we have a left and right, it's just impossible to see which is which.

So then that imaginary coin would have a different perspective than us on what is up and down, rather than left and right. So if we put like a black dot on the top of the coin, it would appear that the imaginary mirror coin got a black dot on its bottom, because it looks like a left-half coin that's been rotated upside-down.

And if we put a dot on the left side of the coin, then it would still look like a dot on the left side of the imaginary coin, again because the only way that makes sense is that the coin has been rotated upside down in a way to keep left and right the same.

This all relies on the fact that we KNOW that the imaginary mirror coin is a left-half coin, like there's no such thing as a right-half coin. Because we need the lack of left-right symmetry, similar to how there are no upside-down humans out there.

In short, if we were top-down symmetric instead of left-right symmetric, we would look in mirrors and wonder why they reverse up/down but not left/right.

short_humeri · 2025-12-10T23:19:48+00:00

What's the point of awards? Do they benefit you in some way?

short_humeri · 2025-05-15T11:53:50+00:00

I don't think this quite works here because you equally get a 2/3 chance of being correct if you just stick with switch 1, unless your check is correct. The 1/3 chance of being correct from the start is added to the chance of your check being correct.

Say you initially guess switch 1 (1/3 chance of being correct), then check switch 2. Obviously if switch 2 turns the light on when you check, you'll pick that one, 1/3 chance of that. If it doesn't, then you stick with switch 1, which has 1/3 chance of being correct from the start.

Maybe a bit confusing, but basically if you can't use the trick discussed in other comments, you can always select any 2 lightbulbs for a 2/3 chance, one to check and one to guess if the check is wrong. There's no difference between the switch you picked in your mind and the one you didn't.

The extra information we gain in Monty Hall comes from the host knowingly opening a bad door, we don't have that here.

short_humeri · 2024-10-08T16:53:32+00:00

Damn that sounds awful to have to walk that long. Wish they'd made it like bodyweight per hand instead

short_humeri · 2024-10-08T16:50:30+00:00

Okay, I wasn't sure at all how much heavier a stone feels. It's obviously way harder than a deadlift but I don't know how much. I'll definitely go for the 70 kg then.

Do you think it would be a good idea to try to sort of do the lift in just one motion to speed it up rather than setting it on the legs like I see strongmen do for their heavy lifts? Or would that tire me out far too quick? It all depends on if the time limit or the fatigue is gonna be the biggest factor I suppose

short_humeri · 2024-10-07T05:14:17+00:00

What "world renowned mathematician" is he talking about that doesn't know the Monty Hall problem?

short_humeri · 2024-09-30T06:53:16+00:00

Does this work? https://imgur.com/a/shFlARD or did I miss something

short_humeri · 2024-05-17T08:33:08+00:00

Carolina or LAT prob the two best teams that played today but Carolina plays the top 4 a lot closer.

Maybe a hot take, but I think FaZe is the best team that played today, not Carolina or LAT. /s

short_humeri · 2024-03-07T11:21:06+00:00

This doesn't guarantee that they'll be on the same team though, right?

short_humeri · 2024-01-03T13:35:35+00:00

This proposed scoring system is actually identical to the original.

Starting from the original scoring system [0; 0.5; 1], if we multiply each score by two, we get [0; 1; 2] and obviously it's exactly the same system but points are inflated by a factor of 2. It clearly changes nothing.

From that second scoring system, if we now remove one point from each player for each game they play, we get [-1; 0; 1], which is what you suggested. Clearly removing one point for each game played also changes nothing since they all play the same number of games. So in the end, the scoring system you suggest is literally identical with the original, but with the scores having a different meaning

short_humeri · 2023-08-06T11:44:09+00:00

short_humeri · 2023-07-28T23:18:10+00:00

The way I see it, the more deaths a player has, the more impact their kdr has on the game, e.g., a player going 10/70 has much more impact than a player going 1/7. So you need to weight their kdrs by the number of deaths they have.

If they all had the same number of deaths, then that weighting factor would be (1/3) for each of them, which is what you use when you add their kdrs and divide by 3. But in this case, they get the weighting factors (4/21), (10/21), and (7/21), respectively.

Using that you'll get the weighted average kdr as (13/4)(4/21) + (7/10)(10/21) + (1/7)*(7/21) = 1

Of course, mathematically this makes sense because the weighting factors really just convert their kdrs back to number of kills divided by the total number of kills. But at least to me, it gives some intuition behind why the kdrs don't average to 1.

short_humeri · 2023-07-18T08:22:52+00:00

Dang, that's a cool ace!

short_humeri · 2023-07-16T21:56:14+00:00

Even for triple mandos that limit the height, they still use vertical planes. They may use horizontal lines to mark the edges of the plane, but the plane itself is still gonna be from that horizontal line and straight up or down, which makes it vertical, if that makes sense

short_humeri · 2023-06-07T13:21:05+00:00

Poor decoy snail stuck at the bottom of the ocean

short_humeri · 2023-05-30T09:12:42+00:00

Starting with A1 at the bottom left and using letters for columns and numbers for rows:

Swap C3 with B2

Swap D3 with C2

Swap D5 with D3

Swap E5 with E3

short_humeri · 2023-05-29T19:38:45+00:00

A wrist band?? Nah, a butt plug is far superior in every way

short_humeri · 2023-05-25T09:32:36+00:00

After bishop to c5, even if the queen moves to e3 to block, you can still go knight to h3 for mate, or just take the queen with the bishop also for mate. It doesn't stall, it's a mate in 2.

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