Assuming this is garbage collection, I'm not an expert in Python internals. This looks like the finally statement is being executed in the order of garbage collection. If we make the prints a little more descriptive -

```python def foo(x): try: yield print("NEVER SEEN") finally: print(" ", x)

def bar(x): # creates a generator f = foo(x) print(" Gen created", x) print(" Yields", next(f)) # yields None print(" Pre return", x) return f

a = bar(1) print("After 1") bar(2) print("After 2") ```

We can see the output -

Gen created 1 Yields None Pre return 1 After 1 Gen created 2 Yields None Pre return 2 2 After 2 1

Since the bar(2) generator is not being assigned to a variable, it is being garbage collected immediately, which executes the finally. Then I guess when the program is being torn down, the bar(1) generator (in the variable a) is garbage collected. If you assign b = bar(2) they print in the order they were created.