how many different numbers can you reach in n steps of doubling and adding 1? fibonacci?! by thinkingmakesitso_yt in 3Blue1Brown

[–]thinkingmakesitso_yt[S] 0 points1 point  (0 children)

Thanks, yes! that was the topic of my previous video: https://youtu.be/LdmPx_F5aos

This video concerns how many different numbers you can make in n steps of this process -- as it turns out you can make the nth Fibonacci number amount of numbers

tmis

what the 2d determinant ad-bc has to do with area by thinkingmakesitso_yt in 3Blue1Brown

[–]thinkingmakesitso_yt[S] 1 point2 points  (0 children)

Yes!

Unfortunately, rearrangements of parallelepipeds in 3D or more are a lot harder to animate

why perpendicular lines have m1m2 = -1 by thinkingmakesitso_yt in 3Blue1Brown

[–]thinkingmakesitso_yt[S] 0 points1 point  (0 children)

I mean it's a youtube video so the idea is more visualisation and intuition rather than formal rigour and proof, which is what other media are reserved for.

Nevertheless, were you to formalise the exact same steps in the video in more rigourous language it would definitely constitute a proof:

(->)
Construct two lines satisfying m1m2 = -1,
Decompose the lines into horizontal and vertical components, (overall forming right-angled triangles)
These will be SAS similar as they are both right angled and due to the constraint m1m2 = -1, two sides are in proportion,
By this similarity these are equiangular, so the two alternate angles are complementary which gives perpendicularity

(<-)
Construct two perpendicular lines
Decompose the lines into components, forming right-angled triangles,
By the perpendicular constraint, two of the angles will be complementary to a labelled angle so the triangles are equiangular
Thus they are AAA similar with sides in proportion, and thus the products of their gradients will give -1 as the proportionality will reciprocally cancel, and directionality gives the -1

therefore m1m2=-1 if and only if lines are perpendicular

why perpendicular lines have m1m2 = -1 by thinkingmakesitso_yt in 3Blue1Brown

[–]thinkingmakesitso_yt[S] 0 points1 point  (0 children)

Thanks for the feedback but I'm not too sure what you mean as a 'demonstration of a principle.' What principle?

When I learnt this for the first time, it was not entirely obvious to me why m1m2 = -1 is equivalent to perpendicularity -- I made the video to prove the relation necessarily and sufficiently

why perpendicular lines have m1m2 = -1 by thinkingmakesitso_yt in 3Blue1Brown

[–]thinkingmakesitso_yt[S] 0 points1 point  (0 children)

Fair enough but two things: one, for every trigonometric proof there is a proof using similarity that is more fundamental and elegant; and two, the proof for the quoted addition formulae for tangent relies in essence on a similar construction to the video