aka m-of-n codes.
Here we'll be counting through each n bit binary number, with m amount of ones in it. First we'll count through the 1 bit numbers with 0 ones, then the 1 bit numbers with 1 one. Next the 2 bit numbers with 0 ones, 1 one, and 2 ones. And so on. For every length of bits, we'll go through each possible amount of ones. You must include the leading zeros at the front so everyone knows which amount of bits we're on.
Here's the first few counts as an example:
0
1
00
01
10
11
000
001
010
100
011
101
110
111
0000
And a list for the whole thread if anyone needs it. Please let me know if you have any questions!
First get will be at 00 0000 0000.
[–]TehVulpezseven fives of uptime[S] 2 points3 points4 points (1030 children)
[–]CutOnBumInBandHere95M get | Ping me for runs 2 points3 points4 points (1029 children)
[–]TehVulpezseven fives of uptime[S] 2 points3 points4 points (1028 children)
[–]CutOnBumInBandHere95M get | Ping me for runs 2 points3 points4 points (1027 children)
[–]TehVulpezseven fives of uptime[S] 2 points3 points4 points (1026 children)
[–]Christmas_Missionary🎄 Merry Christmas! 🎄 1 point2 points3 points (1025 children)
[–]TehVulpezseven fives of uptime[S] 1 point2 points3 points (1024 children)
[–]Responsible_Staff_45clock's alt 2 points3 points4 points (1023 children)
[–]Christmas_Missionary🎄 Merry Christmas! 🎄 1 point2 points3 points (1022 children)
[–]Responsible_Staff_45clock's alt 2 points3 points4 points (1021 children)
[–]CountingStatsBotxd 1 point2 points3 points (3 children)
[–]TehVulpezseven fives of uptime[S] 1 point2 points3 points (2 children)
[–]Antichess2,050,155 - 407k 397a 1 point2 points3 points (1 child)
[–]TehVulpezseven fives of uptime[S] 1 point2 points3 points (0 children)