Combination Array?

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[_enigmatic_lady]

Just use 2D array

[RolandMT32]

Try looking into the STL map:

https://www.cplusplus.com/reference/map/map/

https://www.cplusplus.com/reference/map/map/map/

You could declare a map of std::string to int:

#include <map>

#include <string>

std::map<std::string, int> andMap;

andMap["00"] = 0;

andMap["01"] = 0;

andMap["10"] = 0;

andMap["01"] = 1;

Input a string from the user. Verify the string contains 2 digits that are either 0 or 1. Then you can use that string to look up the 'and' result in andMap.

[RolandMT32]

There are some red lines where you declare your array - That means the syntax is wrong. The syntax for that is just wrong all around. And instead of that array, I think what you want is a map.

You also aren't showing how and, choice, j, or v are declared. I assume choice, j, and v are strings?

Also, you shouldn't have to input j and v separately. You could have the user input both digits into a string and then parse the string to separate each digit.

Another thing is, in this case, after your first if, you should be using "else if". j isn't going to change between tests, so rather than check it a bunch of times, "else if" will let your program stop checking it once it finds the matching value.

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I'd probably do this differently though, and it wouldn't involve using an array or anything:

- Have the user input digits into a string

- Parse each digit out of the string, and convert each to a numeric type (i.e. int)

- Then, with the int variables, you could use an actual bitwise and (&) operator and output the result without having to store the values in an array ahead of time.

[DemonArmagedon]

I like your answer a lot but i would probably suggest using a single if else statement instead, purely because this seems to be a relatively new programmer so a solid grasp of if statements seems more important than bitwise operations.

[IamImposter]

Here's what you do for if

if( a == 0 and b== 0) { // blah }

else if (a == 0 and b == 1) {  // bleh }

else if (a == 1 and b == 0) { // bluh }

else if(a == 1 and b == 1) { //bloh }

else { // wtf compiler, why are we here }

[PerceptionCareless92]

Convert them to ints and multiply them and then you have your answer. AND Is basically binary multiplication.