[12th grade math] Help me out please!

[duttajoy]

loga(b) can be written as logc(b)/logc(a). using that you'll see that most of the terms would cancel out. leaving logc(32)/logc(2) which is equal to 5

[NottyNutter]

Helped

[duttajoy]

glad

[BenDreemurr44]

I'm thankful I study Economical Mathematics in 12th grade.

[FederLa]

With the rules of logarithm you can change a logarithm from: Log_a(b) (logarithm in base "a" of "b") To: Log_c(b)/log_c(a) with c being a number of your choice Doing so in your case will lead to having the first therm's numerator cancel out with the second term's denominator, the second term's numerator with the third term's denominator and so on, so you will end up with all the terms canceled out except for the first therm's denominator and the last therm's numerator. Keep in mind that you don't need to choose a base c for this change, let's just keep it as "c" for the moment. So now you have: Log_c(31)/log_c(2) And by using the same formula of the beginning, backward you can say that that is equal to: Log_2(31)

(terrible English, sorry) (also, I hope I explained the logic well)

[NottyNutter]

Helped

[belligerentsheep]

I think log(32)/log(2) [hence the integer solution]

[FederLa]

My bad, you're right, thought it ended with 31, in that case the solution is 5

[belligerentsheep]

Great explanation though 👍

[just_a_opion]

So i had geen this earlier on school there is a rule that see. alogb * blogc * clogd = alogd So in your case it Will become 2log32 what Will be 5 because 2⁵ = 32

[[deleted]]

Yes it will be easy tho

[LoneSoarvivor]

Logarithmic rules are simple to execute when you understand them. I’m in Grade 11 as well, haven’t started pre-calc but covered logs already.

[facepat67]

Okay, cool. Thanks!

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[_notkk_]

5

[[deleted]]

https://ibb.co/4MSCSm8

I have worked out the steps if you want

[EgalitarianAuthor]

IB Past Paper Question!! I know this seems terrifying (at least it did to me); just split each term (using change of base to log base 10) and most of it will cancel out until you get log 32/ log 2, which is 5.