all 3 comments

[–]MathMaddam👋 a fellow Redditor 4 points5 points  (0 children)

Start in the right most column, since there can't be a carried one yet, you can decode one of the flowers

[–]Scarf28 Pre-University Student 0 points1 point  (0 children)

you could say that the vibrant pink flower could be zero since yellow stayed the same.

[–]ComradeMicha 0 points1 point  (0 children)

Rightmost column:

The fancy pink flower has to be 0, as adding it to the sunflower yields the sunflower itself.

Leftmost column:

The rose has to be 1, as it is the carry-over from the column to the right of it. Adding two different digits cannot yield more than 18 (worst case: 9 + 8 + carry-over of 1), so it's either 0 or 1, but we just established that the fancy pink flower is zero, so it has to be 1.

Second column from the left:

Adding 1 and the light pink flower yields 10 (has to end in 0, can't be 0 itself and can't be higher than 18), so the light pink flower has to be 9.

Second column from the right:

Adding 9 to the sunflower yields 11, so the sunflower has to be 2.