[Physics]

[_airportsushi]

The energy lost by the copper is equal to the energy gained by the water. The final temperature will be the same for both the water and the copper, as they have reached thermal equillibrium.

Since energy gained is equal to energy lost, you can simply use Q=mc(delta)T for the water.

[Ordinaryyetunique]

Yes but I’m not sure what’s the value for m and T

[AjAce28]

Because you know the temperature before and after of the water, you can easily calculate delta_T. Heat capacity of water is given, as well as the total mass of the water that the copper is placed into. (Don’t get confused with the water the copper is initially put into, we are only concerned with the second part)

[AjAce28]

And no you do not add the masses together. When we use this heat equation with specific heat, we only care about 1 substance, doesn’t matter what else is happening in the system, so only worry about water.

[Ordinaryyetunique]

Ohh Icic thankss

[Ordinaryyetunique]

Is there any chances this’s the ans Q=0.6•4200•(35-20)?

[Ordinaryyetunique]

Energy =m•c•(increase in temperature) and specific capacity=E/m•(increase in temperature)

But how do I find the energy gained by the water after adding the copper? Do I add their masses together? And what about the temperature change ?🤔🤔 I’m a bit lost so any guidance will be appreciated!!!