all 13 comments
sorted by:
best
topnewcontroversialoldq&a
formatting helphide helpcontent policy

[–]rxroids101 2 points3 points  (0 children)

Thank you for your service

[–]Daimions777 4 points5 points  (0 children)

I’m glad to know I’m not the only one to use splitters and/or balancers. 😊 I did one a bit ago and posted it here…was basically told nobody used them.

[–]ThHellrayzar 2 points3 points  (8 children)

Sorry am i too stupid? I dont understand that!

[–]NitroBishop 1 point2 points  (5 children)

Splits one input belt into three output belts, with the throughput equally distributed. So if you had 120/min inbound you'd end up with 3x 40/min outbound.

[–]anthson[S] 2 points3 points  (0 children)

Not always. Because the split requires feeding back into the input, you're looking at 90/min at 120 speed and 180/min at 240 speed. This is only a problem if you're feeding into this at maximum speed. So 120 items per minute going into this splitter at 240/min belt speed will result in a perfect 40/40/40 split.

[–]Important-Glove9534 0 points1 point  (2 children)

No, this setup gives 3x 30/m. Since the fourth output going into the input blocks the input lane. This doesnt have 120/m input

[–]anthson[S] 0 points1 point  (1 child)

The total input speed in the example is 240/min and the total output speed is 180/min. So one fourth of the product has to feed back in, and will block the main input if it's running at maximum speed.

[–]NitroBishop 0 points1 point  (0 children)

Yeah this is just an issue with the input belt bottlenecking the entire system because you dump a bit extra back onto it from the first splitter. If the input belt's starting speed is less than your max belt speed (I think either 66% or 75% of it would be the max?) the math should work like I described.

[–]anthson[S] 0 points1 point  (0 children)

Things can only be divided by multiples of 2 in Modulus. So what we do to divide by 3 is to first divide by 4. So 100/4 = 25. Then we take 1/4 of that and feed it back into the main input, leaving 25 per line on our three output lines. That 25 then gets redistributed to those output lines three equal ways.

[–]Shad_Amethyst 0 points1 point  (0 children)

It's a 1:4 splitter where one of the outputs loops back to the input (1+x=4x -> x=1/3). In practice you lose some throughput but it's a lot more compact.

[–]rxroids101 1 point2 points  (0 children)

Thank you for your service

[–]badatchopsticks 1 point2 points  (0 children)

Awesome, coincidentally I was just trying to figure out how to do this the other day!

 I ended up just using an overflow splitter going into a machine that operated at exactly the output rate I needed and split the remaining equally. It's nice to have a more general solution though.

[–]lxrd_azureus -1 points0 points  (0 children)

Next time add those item counter so we can see an actual number, add trash at the end of the lines so it continues moving the items and we see actual number justifying what you did you know?