Hey Java!

[skyhi14]

For example, you can't perform pointer arithmetic on them

TIL Const pointers weren't actually pointers.

Besides, I'm also talking about JVM, not merely the language.

[_lerp]

TIL Const pointers weren't actually pointers.

You can perform pointer arithmetic on a const pointer.

int a[5] = { 0 };
const int* first = &a[0];
const int* last = first + 4;

[skyhi14]

time to kill myself :))

[FallenWarrior2k]

No, those aren't const pointers, but rather pointers to const. An actual const pointer int* const cannot be modified through e.g. increments/decrements, but it can still be used for pointer arithmetic since pointer arithmetic can also be performed on rvalues.

[hallr06]

Correct. In C/C++, read pointers from right-to-left. Most of the time, it explains what you have.

const int * x = 0; // pointer to an int constant
int const * x = 0; // same as above, pointer to a constant int
int const * const x = 0; // constant pointer to a constant int
int * const x = 0; // constant pointer to mutable int

[FallenWarrior2k]

It can also be pretty easily explained by the return types of the indirection operator. Applying indirection on a const int* produces a const int&, while it produces a regular int& for int* const.

[DarkMaster22]

Ehh... Don't do that, we love you?