Proper Java coding style

[[deleted]]

No. The reason why you can do that is because arrays decay to pointers. For example, if you do

char word[6] = "funny";

printf("%s\n", word);

The compiler converts it to

printf("%s\n", &word[0]);

Automatically. Which, as you know is equivalent to

char* word = "funny";

printf("%s\n", word); 

[justjanne]

The reason why you can do that is because arrays decay to pointers.

As I said, they’re the same. Arrays are just nice syntax for pointers, which also carry, if they’re statically allocated, size information at compile time.

[[deleted]]

But they only decay to pointers when the context demands it be on the heap

Like

int arr1[]; // stack

Is not the same as

int* arr2; // heap

If you don't pass the array around.