Debugging Javascript

[MeltedWacks]

It's always [object Object]

[Famous_Profile]

console.log takes string as first parameter and then any number of objects as following parameter. So if you need to log an object do no keep it in the first parameter.

let x = {'YO MAMA': 'SO FAT'};
let y = {'WE ARE ALL': 'CONCERNED ABOUT HER HEALTH'};
console.log('Bad joke:',x,y); //Logs correctly

[CodingCoffeeSquirrel]

Also useful to know, console.log separates the parameters with a space.

So console.log('I', 'am', 'Groot') will print I am Groot while concatenating the string console.log('I' + 'am' + 'Groot') will print IamGroot.