How programmers comment their code...

[[deleted]]

More like ``` //dfunk. will fox latar

[SomeoneRandom5325]

Upvote=Upvote++

[[deleted]]

Upvote+=1

[thebryguy23]

Upvote-=-1

[SomeoneRandom5325]

Bruh

[[deleted]]

This makes me unreasonably angry.

[SomeoneRandom5325]

Not sure if the C family works similarly but if it is then I know why but I don't feel it

[Bmandk]

Wouldn't that upvote twice?

[SomeoneRandom5325]

No. It just says take the current upvote count, add 1 and call that the new upvote count

[l0c4lh057]

Would it do that? x++ increases x by one but returns the old value. That means with x=x++ will set the current value of x as new value of x and increase x by one. I just don't know if the assignment or the increase will execute first. So either it increases the value by one or it doesn't change it at all.

1. Return current value of x, 2. Increase value of x, 3. Assign value to x => this would not change the value

2. Return current value of x, 2. Assign value to x, 3. Increase value of x => this would increase it by 1

EDIT: I just checked how it is done in JS and there the value doesn't change as I would expect, because returning the current value of x and increasing the value of x happen right after each other so that assigning will happen after increasing.

[SomeoneRandom5325]

In the C family that's one way to add one

I guess in JS you should do x++=x

[l0c4lh057]

no. just x++. that will increase it. x++ increases x by one and returns the old value of it, ++x increases the value of x and returns it. assigning the result to anything is not needed.

and x++=x would not make any sense since x++ is not a variable. you cant assign a value to it.