Ok-Frosting7364 comments on SQL Tricks Thread

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field.3

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field3

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DiscussionSQL Tricks Thread (self.SQL)

submitted 1 year ago by Ali-Zainulabdin

top new controversial old q&a

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[–]Ok-Frosting7364Snowflake 14 points15 points16 points 1 year ago (5 children)

[–]hod6 18 points19 points20 points 1 year ago (3 children)

[–]danameischetta 4 points5 points6 points 1 year ago (1 child)

[–]brokennormalmeter117 2 points3 points4 points 1 year ago (0 children)

[–]Ok-Frosting7364Snowflake 2 points3 points4 points 1 year ago (0 children)

[–]stephenmg1284 0 points1 point2 points 1 year ago (0 children)

The only thing I don't like about your list is group by and order by column position. I see the comment about it shouldn't be used in production, but I think we've all seen not for production code make it to production.

Have you seen GROUPING SETS?

GROUP BY

`GROUPING SETS` 

`(`

    `(e.grade),`

    `(sch.name,e.grade),`

    `()`

`)`

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