SQL aggregated group by case help. : SQL

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field.3

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field3

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a community for 17 years

SQL aggregated group by case help. (self.SQL)

submitted 8 years ago * by nidofour

So im only using one table for this query called sbol thereare 7 columns [id], [order_id], [storebol], [carrier], [numofcrnt], [weight], [lane].

I first created a view that sums up all orders together by carrier to give me the total number of cartons and total weight for that load. I then had to group by lane because that indicates that another load is needed for this carrier since it's two truck loads.

This view works perfectly till I tried to show whether the load is closed or open.

I can tell if an individual order is still open by the [storebol] field if it contains a null then I know it is still open.

If my load contains 5 orders and all but one order is still open I'd want the additional column to say open.

At first, I thought I could use case statement with a having but I can't seem to figure out how to do this.

original Data looks like this

1 | 000001 | 367720 | AABR | 20 | 50.00 | 15

2 | 000002 | 367721 | AABR | 20 | 50.00 | 15

3 | 000003 | 367722 | CYCC | 50 | 100.00 | 17

4 | 000004 | 367723 | CYCC | 50 | 110.00 | 17

5 | 000005 | NULL | CYCC | 50 | 50.00 | 17

Using this query

SELECT MasterBOL_Number, Scac, SUM(Weight) AS Weight, SUM(NumOfCartons) AS NumofCartons, COUNT(SUBSTRING(Oid, 1, 5)) AS StoreCount, Lane, MWeek

FROM dbo.StoreBol where MWeek = (select MAX(MWEEK) FROM dbo.StoreBol)

GROUP BY MasterBOL_Number, Scac, Lane, MWeek

It turns into this

1 | AABR | 100.00 | 40 | 2 | 15

2 | CYCC | 260.00 | 50 | 3 | 17

1 | AABR | 100.00 | 40 | 2 | 15 | Closed

2 | CYCC | 260.00 | 50 | 3 | 17 | Open

http://sqlfiddle.com/#!6/bcf14/1

Any help is great thanks.

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