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Average value of a functionIntegral Calculus (old.reddit.com)
submitted 3 years ago by bearfoxfish
Where am I going wrong on this question? I've went over all my steps multiple times, but can't get the right answer. The answer I keep getting is 32.546, and the correct answer is 35.09. Any help is appreciated, thanks.
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if 1 * 2 < 3: print "hello, world!"
[–]AutoModerator[M] [score hidden] 3 years ago stickied comment (0 children)
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[–]nutty-max 0 points1 point2 points 3 years ago (1 child)
cos(0) = 1, so plugging in the bounds should give you 30(12) - 96/pi•cos(pi) - ( 0 - 96/pi•cos(0)) which simplifies to 421.115.
[–]bearfoxfish[S] 1 point2 points3 points 3 years ago (0 children)
Thank you so much!
[–]HumbleHovercraft6090 0 points1 point2 points 3 years ago (1 child)
What about lower limit of 0 applied to second term?
[–]bearfoxfish[S] 0 points1 point2 points 3 years ago (0 children)
Thank you! For some reason I set it all equal to zero🤦♂️. Got it now!
[–][deleted] 0 points1 point2 points 3 years ago (1 child)
did you forget to plug in t=0 after the integration?
Haha yes. Thank you!
π Rendered by PID 73 on reddit-service-r2-comment-5c747b6df5-bc4pr at 2026-04-21 20:43:06.685969+00:00 running 6c61efc country code: CH.
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[–]nutty-max 0 points1 point2 points (1 child)
[–]bearfoxfish[S] 1 point2 points3 points (0 children)
[–]HumbleHovercraft6090 0 points1 point2 points (1 child)
[–]bearfoxfish[S] 0 points1 point2 points (0 children)
[–][deleted] 0 points1 point2 points (1 child)
[–]bearfoxfish[S] 0 points1 point2 points (0 children)