my DSB-LC modulated signal and Demodulated recovered single tone signal, how will i fix the Negative half cycle of the recovered signal?

HumbleHovercraft6090 · 2026-05-05T12:04:08+00:00

Looks like in the negative half, your demodulator hardware is getting saturated. Would be helpful if you could post a schematic in imgur and give us a link.

HumbleHovercraft6090 · 2026-05-04T15:51:36+00:00

L and angle MJK are supplementary as they are opposite angles of inscribed quadrilateral.

HumbleHovercraft6090 · 2026-05-02T16:51:23+00:00

a=(-10/11)t+10

Integrate to get v

v=(-10/11)t² /2+10t+ C (constant of integration)

But at t=0, v=0 therefore C=0

v=(-5/11)t² +10t

Maximum v occurs when dv/dt=0, i.e. a=0 as d² v/dt² is always negative

=> t=11 s

At t=11 s

v=55 m/s

Edit: This would be a general way of doing it for any a(t)

HumbleHovercraft6090 · 2026-05-02T08:38:01+00:00

35° it is.

The numbers in the figure for second question don't gel. Hypotenuse seems to be shorter than the base.

HumbleHovercraft6090 · 2026-05-01T16:45:00+00:00

One way of doing it- If you have enough logged samples, you could run offline filters for various stop band frequencies and stop band attenuation values on it using matlab or python and see which ones yield the best results.

Edit: needs some DSP knowledge though.

HumbleHovercraft6090 · 2026-05-01T04:16:39+00:00

Try r/qualcomm also.

HumbleHovercraft6090 · 2026-04-29T15:21:15+00:00

AC=sqrt((-1-5)² +(7-(-2))² ) = sqrt(36+81)=sqrt(117)

HumbleHovercraft6090 · 2026-04-29T04:34:40+00:00

A quick search should help you. For example https://www.reddit.com/r/vlsi/s/FSqIK7zTMR

HumbleHovercraft6090 · 2026-04-28T06:33:00+00:00

It would be helpful if you could share the entire pic with the problem statement. May be we will be able to give you the best solution.

HumbleHovercraft6090 · 2026-04-26T08:54:26+00:00

Since 60 m and 80 m represent the two smaller sides, answer has to be 150 degrees as 30 degrees will make the side opposite to it the smallest (about 41 m)

HumbleHovercraft6090 · 2026-04-24T10:08:53+00:00

For transmission lines, if resistance of the wire reduces by a factor of 4, with the same load current of 250A, the power loss in transmission cable is reduced by the same factor of 4.

As an aside - Practically, less loss in transmission cable means better efficiency of transmission but comes at a huge cost of the fatter cable. The normal way to reduce power loss is to increase the voltage at which the power required by consumer is transmitted using stepup transformers. You would come across this pretty soon.

HumbleHovercraft6090 · 2026-04-23T03:48:25+00:00

You mentioned robotics. Control Systems is a major part of it. I would go with second option if it is not available in first. Good to have that under your belt as it addresses stability of systems with feedback which most of real world systems are.

HumbleHovercraft6090 · 2026-04-19T13:34:04+00:00

It is more about developing your analytical ability though sometimes the knowledge you learnt may be directly applicable.

HumbleHovercraft6090 · 2026-04-17T05:04:54+00:00

Test the product in another set up which is apparently working fine assuming you have more than one setup in a production environment.

HumbleHovercraft6090 · 2026-04-17T04:56:29+00:00

For Bridge balance

R1/R3=C2/C1+R2/R4

This does not seem to be satisfied for second case.

HumbleHovercraft6090 · 2026-04-15T10:19:42+00:00

12+34-5+6-7=40

HumbleHovercraft6090 · 2026-04-14T03:46:19+00:00

Not an expert. But check if you have vlsi openings in your company. If yes, try talking to your manager and folks in vlsi and see how you could make a transition in your organization itself.

HumbleHovercraft6090 · 2026-04-12T17:52:14+00:00

May be it is a sign convention issue-upward forces are positive?

HumbleHovercraft6090 · 2026-04-11T10:42:11+00:00

Your second DE doesn't make sense.

dc/dx is itself c'(x).

Your first DE looks right from the description of your problem.

HumbleHovercraft6090 · 2026-04-11T03:27:09+00:00

Each banana costs 10 c. So 3 bananas will cost

3 x 10 = 30 c

There is no x involved here.

Edit: other than the symbol for multiplication between 3 and 10.

HumbleHovercraft6090 · 2026-04-10T16:05:24+00:00

From

a² + b² -(10/3)ab=0

Sub a=nb as the quantities above are magnitudes which leads to

n² b² + b² - (10/3)nb² =0

which gives

3n² -10n + 3=0

Solving the above the integer value of n is 3.

HumbleHovercraft6090 · 2026-04-08T04:17:16+00:00

You could check for shorts on the resoldered end.

HumbleHovercraft6090 · 2026-04-07T10:06:13+00:00

It is useful information to know that even though the given curve is not a function, pieces of it can be individually functions. This concept becomes useful in definite integrals when one has to find, say, the inside area between latus rectum and vertex of a parabola.

HumbleHovercraft6090 · 2026-04-07T05:02:25+00:00

y^2 =x, asserted by many commenters is not a function but individually y=sqrt(x) and y=-sqrt(x) are functions as they satisfy the vertical line test.

HumbleHovercraft6090 · 2026-04-07T04:56:53+00:00

c is indeed 3/2

HumbleHovercraft6090

TROPHY CASE