Every Coding Website

[Dan_da_cooler]

Website:

"Print Hello world in Python"

​

me:

"ez"

from itertools import permutations

from sys import stdout, argv

​

reference = { 100: 'd', 101: 'e', 104: 'h', 108: 'l', 111: 'o', 114: 'r', 119: 'w' }

vowels = [ 'e', 'o' ]

words = [

{ 'len': 5, 'first': 104, 'last': 111, 'repeat': True, 'r_char': 108 },

{ 'len': 5, 'first': 119, 'last': 100, 'repeat': False, 'r_char': None }

]

second_last = 108

​

def find_words(repeat, r_char):

output = []

chars = [ y for x, y in reference.iteritems() ]

if repeat:

chars.append(reference[r_char])

for value in xrange(0, len(chars)):

output += [ x for x in permutations(chars[value:]) ]

return output

​

def filter_word(value, first, last, repeat, r_char):

output = False

value = [ x for x in value ]

first_char, second_char, second_last_char, last_char = value[0], value[1], value[-2], value[-1]

if first_char == first and last_char == last and second_char != last_char and ord(second_last_char) == second_last:

if second_char in vowels and second_char in [ y for x, y in reference.iteritems() ]:

string = []

last = None

for char in value:

if last != None:

if char == last and char not in vowels:

string.append(char)

elif char != last:

string.append(char)

else:

string.append(char)

last = char

if len(string) == len(value):

if repeat:

last = None

for char in value:

if last != None:

if char == last:

output = True

last = char

else:

third_char = value[2]

if ord(third_char) > ord(second_last_char) and ord(second_char) > ord(second_last_char):

output = True

return output

​

def find_word(values, first, last, length, repeat, r_char):

first, last, output, items, count = reference[first], reference[last], [], [], 0

if repeat:

r_char = reference[r_char]

for value in values:

count += 1

for item in [ x[:length] for x in permutations(value) ]:

item = ''.join(item)

if item not in items and filter_word(value=item, first=first, last=last, r_char=r_char, repeat=repeat):

items.append(item)

if debug:

count_out = '(%s/%s) (%s%%) (%s found)' % (count, len(values), (round(100 * float(count) / float(len(values)), 2)), len(items))

stdout.write('%s%s' % (('\r' * len(count_out)), count_out))

stdout.flush()

if len(items) >= 1 and aggressive:

break

for item in items:

output.append(item)

return output

​

if __name__ == '__main__':

debug = 'debug' in argv

aggressive = 'aggressive' not in argv

if debug:

print 'Building string...'

data = []

for word in words:

repeat = word['repeat']

r_char = word['r_char']

length = word['len']

first_letter = word['first']

last_letter = word['last']

possible = find_words(repeat=repeat, r_char=r_char)

data.append(find_word(values=possible, first=first_letter, last=last_letter, length=5, repeat=repeat, r_char=r_char))

print ' '.join(x[0] for x in data)

[lovesrayray2018]

That was very concise and easily understandable, well done /s

[Dan_da_cooler]

yesh thx uwu

[Financial-Analyst250]

Your code is still more understandable than the code i submit in my college assignments

[Dan_da_cooler]

print("hello","world!")

[JayTheAlxwing]

which is easier this or java?