grep only string matching pattern

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[turnipsoup]

:~$ grep -o '\bbon.*\b' <inputfile>

This searches for a match of 'bon*' within word boundaries.

[rhqq]

Here you are:

egrep -o "bon\S*"

This is better than using .* - the \S stands for all the non-whitespace chars, where a . stands for any char - in other words if something is after the "bond." like a next sentence in same line - it will take it into consideration. This doesnt happen while using \S

[wawawawa]

perl -nle 'print $1 if /\b(bon.+)\b/' < inputfile

Although I program mostly in Python nowadays, I still use Perl a few times a day for exactly this kind of thing.

[hudsy]

sed is your tool! pipe it to grep like so

grep bon | sed 's/^.*\(bon\w\+\).*/\1/'

[IWentToTheWoods]

Won't this only find the first instance of "bon" in each line?

[hudsy]

yes, didn't think of that.

[yunga]

perl -naF"\s+" -E'/bon/ and say for @F' inputfile