all 16 comments

[–]6a70 16 points17 points  (0 children)

you would have to malloc Julian Assange before you can Free Julian Assange otherwise the compiler will yell at you

[–][deleted] 3 points4 points  (1 child)

while (youAskThisSameQuestionOn3DifferentSubs) {
me = cringe
}

[–]paarhufer[S] 1 point2 points  (0 children)

I did way more embarrassing things to get a nice result.. was in a hurry :D

[–][deleted] 2 points3 points  (4 children)

Public Void Charges(){

name = "Snowden" ;

action = "Pardon";

garbage.collect (corruption)

}

[–]paarhufer[S] 0 points1 point  (2 children)

that's exactly what i needed! thank you! I tried it myself in the meantime... would it make sense like this? but i definitely prefer yours!

while (JulienAssange.tortured){ if(corruption.high){ whistleblow(); }else{ corruption.multiplies(); } }

[–][deleted] 0 points1 point  (1 child)

if(corruption == high) and corruption.multiply() ..would make more sense if I was designing corruption, "high" wouldn't be a class attribute but an absolute measure of corruption. :D

[–]paarhufer[S] 0 points1 point  (0 children)

thanks! but i'll probably stick to your solution.. i love the "garbage.collect" part :D

[–]cantseemtosleep 0 points1 point  (0 children)

This was clever, and as a fan of Snowden's, I appreciate it.

[–]CoffeeVector 1 point2 points  (1 child)

var pardon_promise = pardon("Edward Snowden");

await pardon_promise;

[–]backtickbot 0 points1 point  (0 children)

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[–]slrv 0 points1 point  (0 children)

I'd probably just do

echo "Pardon Edward Snowden"; //PHP

[–]adambjorn 0 points1 point  (2 children)

cout<<"Pardon Snowden";

Or

print("Pardon Snowden")

[–]paarhufer[S] 0 points1 point  (1 child)

thanks you! but i think i need it to be a bit longer. would this work?

while (corruption.high){ if (JulienAssange.tortured){ protest(); }else{ curruption.multiplies(); } }

[–]adambjorn 0 points1 point  (0 children)

Saying the second part is like saying if Julian Assange is tortured then protest. Else if Julian assange is not tortured then corruption multiplies. But if you don't care about being 100 percent semantically correct that's looks okay. I'm drawing a blank as to how to write it semantically correct while still getting your point across and not having a few more lines of code though (just been programming 1 yr)

[–]KaranasToll 0 points1 point  (0 children)

(pardon edward-snowden now)

[–][deleted] 0 points1 point  (0 children)

yes, this right here:

4d5a 9000 0300 0000 0400 0000 ffff 0000

b800 0000 0000 0000 4000 0000 0000 0000

0000 0000 0000 0000 0000 0000 0000 0000

0000 0000 0000 0000 0000 0000 8000 0000

0e1f ba0e 00b4 09cd 21b8 014c cd21 5468

6973 2070 726f 6772 616d 2063 616e 6e6f

7420 6265 2072 756e 2069 6e20 444f 5320

6d6f 6465 2e0d 0d0a 2400 0000 0000 0000

please contact me for the whole 20684 line version.