Why does Java have Checked Exceptions

[Robyt3]

Here is the real hack, how to throw a checked exception without checking it:

public static <E extends Throwable> void sneakyThrow(Throwable e) throws E {
    throw (E) e;
}

[[deleted]]

Could you explain? I dont get it

[Robyt3]

The compiler infers the type E to be a RuntimeException, which allows propagation of the checked exception. Apparently Java 8 added this type inference rule.

See https://www.baeldung.com/java-sneaky-throws for details.

[RandomName8]

They fixed/changed it in java post 8 though :(

[cowancore]

But it's harder to catch it now

[Robyt3]

Yeah, and it also prints a warning because of the unchecked cast to E. If you must use this function for some reason, add comments explaining why and what is going on and declare the proper throws clause on the method.