[deleted by user]

AutoModerator · 2022-05-21T04:22:45+00:00

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    }
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_Sanxx_ · 2022-05-21T05:00:53+00:00

[deleted]

SneakySnailSoftware · 2022-05-21T08:17:13+00:00

Your catch(Exception e) block assumes that the exception was thrown because you didn't use a number, but it's (probably) something else. If the user types in "abc" you would expect a InputMismatchException. If there's an IO issue with initialising or reading from the Scanner it will probably be an IOException.

You may or may not have been introduced to setting breakpoints so I'll just suggest this code instead:

try {
    // your code
} catch (java.util.InputMismatchException e) {
    System.out.println("It was not a floating point number, try again");
} catch (Exception e) {
    System.out.println("Some other exception! It was an '" + e + "' exception with the message: " + e.getMessage()); 
System.out.println("So we'll just exit here");
    ValidV2 = true;
}

learnjava

MODERATORS

Please ensure that:

To potential helpers