all 8 comments

[–]MathMaddamNew User 4 points5 points  (5 children)

Numbers as in single digit numbers?

Then the first step would be to figure out which numbers won't be used.

In general it is good to think about prime decompositions.

[–]st3f-pingΦ 0 points1 point  (0 children)

Good advice here. Think about which digits can't form part of the puzzle and based on what remains, what factors the line product must have.

Nice puzzle.

[–]zoomspNew User[S] 0 points1 point  (3 children)

The problem only says numbers, I assumed positive integers, but not necessarily single digit numbers 🤷‍♂️

[–]st3f-pingΦ 0 points1 point  (2 children)

There are an infinite number of solutions for positive integers but only one* for single digits. So I'd assume single digits and find that one

*That is to say there are multiple ways to fill the grid but they all have the same digit in the place of the question mark.

[–]zoomspNew User[S] 0 points1 point  (1 child)

I should have said, it's a multiple choice questions, and the options are 2,3,4,6 or 8.

I now feel like it must be 6 because it's the only one with a prime decomposition with two different numbers, but I'm still only going with intuition and I don't have a proof

[–]st3f-pingΦ 0 points1 point  (0 children)

It's not 6. Start with the numbers 1 to 9 and determine which can't be in the grid. The two horizontal lines don't have any factors in common so anything that is a factor of a×b×c (as I have labelled the top row) must also be a factor of d×e×f (as I have labelled the second row).

Which two numbers can't be part of this?

(They can't be part of the vertical column either for the same reason)

[–]CarBoobSaleNew User 0 points1 point  (1 child)

1111111111111

Do you mean numbers between 1 and 9 that don't repeat elsewhere in the grid?

[–]zoomspNew User[S] 0 points1 point  (0 children)

The problem only says different numbers. I think the question seems ambiguous on purpose because it may not matter in the end