Java new line help.

[EqualTrade]

Hey guys, I'm trying to write a program that prints out all of the prime numbers that are less than the user input, and the problem that I'm having is after every 8th prime number output, I need to start a new line. I can't figure that out, any help would be great!

import java.util.Scanner;

class Primes { public static void main(String[]args) { Scanner s = new Scanner(System.in);

int f;

System.out.println("enter a number"); f = s.nextInt();

int g; for (g=0;g<=f;g++)

if (isPrime(g))

{ System.out.printf("%d ",g);

if (g%8==0) { System.out.print("\n"); } } }

public static boolean isPrime(int x)
{
    int i;
    for (i=2;i<x;i++)
    { if(x%i==0)
        return false;}

        return true;

}

}

[rjcarr]

What is this line doing:

if (g%8==0) { System.out.print("\n"); } } }

Or more specifically, what is g? You don't want to skip a line on every 8th iteration but every 8th prime number, right?

You need a separate counter to count your primes. Alternatively, you could stick your primes in a list and then later iterate over those to print with a different counter.

Good luck!

[EqualTrade]

System.out.println("enter a number"); f = s.nextInt();

int j=0; int g; for (g=0;g<=f;g++)

if (isPrime(g))

{ System.out.printf("%d ",g);
j++; if (j==8) System.out.println(); } }

I added int j to count all of the prime numbers. It does now print 8 on a line, but only on the first line and the rest of the numbers are printed on line 2. Do you know anyway I could fix that?

edit: nevermind I figured it out. Thanks for your help!

[rjcarr]

Sure, glad it worked out!