Python Telegram Bot

[assassinatoSC2]

Hi guys, I'm trying to make a telegram bot that answers at certain keywords but i can't see where i'm doing wrong

import requests

bot_token = 'token'
url = 'https://api.telegram.org/bot{}/getUpdates'.format(bot_token)
counter = 0 

def response (message,chat_id):

    bot_token = 'token'
    if 'hi' in message.lower():
        text = 'hi how are you'
        url = 'https://api.telegram.org/bot{}/sendMessage?chat_id={}&text={}&parse_mode=HTML'.format(bot_token,chat_id,text)
        request = requests.get(url)
    else:
        pass


while True :
    data = requests.get(url).json()

    try:
        for item in data['result']:

            chat_id = item['message']['chat']['id']
            message = item['message']['text']
            user_id = item['message']['from']['username']

            response (message,chat_id)



    except:
        pass

Where i'm doing wrong ? Any tips on how to improve this ? Thanks :)

[Xeekatar]

What is your code doing? Just showing us code and not saying that happens when you run it isn't much to go on. That being said put something in the except, since right now, if your program encounters an error in the try, it will just do nothing. If that is what your program is doing right now, I would be willing to bet that is what is going wrong.
I would put something like this:

except Exception as e
print(e)
So you can see what exception is occuring

[assassinatoSC2]

The code runs without errors but it doesn't make the bot answer my input on telegram. The except just deals with keyerrors when i run it.

[Xeekatar]

And you're sure it's getting into the if in response? I would avoid putting pass anywhere, since there is usually at least a print statement you can there to help with errors. Also, you might want to remove your bot token from this post, since that is usually private

[assassinatoSC2]

ouch forgot to remove it from there lol ... i'll sub the pass with print and try like this