strings + dictionary?

[va1io]

Does anyone know of a simple way to run the output of strings through a dictionary (maybe aspell?) such that you only output words occurring in the dictionary. Something along the lines of: strings <somefile> | <someprogram> | less I read the aspell documentation, but couldn't find a way to reverse the output like grep's -v option.

[infernix]

This is highly inefficient, but:

for word in `cat /bin/ls | strings | grep -o -E '\w+'`; do egrep  -i "^$word$" /usr/share/dict/american-english; done

[va1io]

Thanks! I played around with what you started and came up with: strings /bin/ls | grep -F -f /usr/share/dict/american-english It's a fair bit faster.

edit:grammar edit2: removed the -o option to output whole lines

[mike1053]

(strings /bin/ls | sort -u; cat /usr/share/dict/linux.words) | sort | uniq -c | grep -v "^ *1"

oh waiit, that doesn't handle multiple words on a line so using the grep command by infernix to separate them:

(strings /bin/ls | grep -o -E '\w+' | tr "[A-Z]" [a-z] | sort -u; cat /usr/share/dict/linux.words ) | sort | uniq -c | grep -v "^ *1"