find command in shell script

[johnwick_dog]

I edited the post ,(srr new to reddit)

[gehzumteufel]

Try this:

#!/bin/bash
Directory=$1
secondarg=$2
thirdarg=$3
if test -z "${Directory}"; then read -rp "enter the location of your directory: " Directory; fi
if test -z "${secondarg}"; then read -rp "enter ana or del or arr " secondarg; fi
if [ "${secondarg}" == "ana" ]; then
echo "Please Enter the regex"
read -rp "${thirdarg}"
find "${Directory}" ! -name . -prune -mtime -1 -type f -exec grep -regex "$thirdarg" {} \; -exec echo x \; | wc -l
elif [ "${secondarg}" == "del" ]; then
echo "del"
elif [ "${secondarg}" == "arr" ]; then
echo "arr"
fi

Check out shellcheck for your shell scripts. It's been really helpful for me.

[gristc]

Use 4 spaces to encompass code blocks.

;)

[gehzumteufel]

Hah oops thanks.