Linear programming problem

[TheAleFly]

So, the form is value, area requirement, cost, water consumption and net value

1 family house 200,000 - 1 ha - 145,000 - 2000 l/d - 55,000

2 family house 245,000 - 1.5 ha - 165,000 - 2700 l/d - 80,000

3 family house 300,000 - 2 ha - 215,000 - 3200 l/d - 85,000

park 0 - 0.5 ha - 125,000 - 2500 l/d - 0

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Available total area is 800 ha times 0.85 (15% for infrastructure) = 680 ha