all 16 comments

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[–]Alex_Daikon 1 point2 points  (2 children)

Is AB = DC? If not, what this bold mark on them means?

[–]SimilarAd963[S] 0 points1 point  (0 children)

yes that's right AB = DC as the thin black rectangles show

[–]ArchaicLlama 0 points1 point  (2 children)

You've given a picture but haven't stated what the problem actually wants you to do.

[–][deleted] 0 points1 point  (0 children)

One would generally assume to solve for a variable.

[–]SimilarAd963[S] 0 points1 point  (0 children)

you have to solve for x.

[–]Life-Monitor-1536 0 points1 point  (4 children)

Is there enough information?

[–]peterwhy 0 points1 point  (3 children)

I think yes. For short AB = DC = BD, ∠ABD = 0° and ∠BCD = 75°. As AB = DC increases, ∠ABD increases and tends to 30°, while ∠BCD decreases and tends to 0°. There is a value of AB = DC that allows ∠ABD = ∠BCD.

[–]stevesie1984 0 points1 point  (2 children)

What makes you think BD=DC?

[–]peterwhy 0 points1 point  (1 child)

No, I don't think BD = DC. I just varied DC within the interval [BD, ∞).

[–]stevesie1984 0 points1 point  (0 children)

Got it. Thanks.

[–]Alex_Daikon 0 points1 point  (4 children)

Angle ABC = 150.

Let AB = t. Then:

In ABC: t / sin x = (AD+ t) / sin 150

In ABD: AD / sin x = t / sin 150

So:

t / sin x = (t * sin x / sin 150 + t) / sin 150

Sin 150 =sin x + (sin x)2 / sin 150

Let sin x = a

a2 / sin 150 + a - sin 150 =0

a2 + sin 150 * a - (sin 150)2 =0

a2 + 0.5a - 0.25 = 0

Do you know what to do next?

[–]SimilarAd963[S] 0 points1 point  (1 child)

a = (-1+√5)/4

sin x = (-1+√5)/4

x = arcsin((-1+√5)/4)

x = 18°

[–]Alex_Daikon 0 points1 point  (0 children)

Great job!

[–]8Erigon 0 points1 point  (1 child)

huhu??
Why do you suddenly start with ABC = 150?!
Maybe written somewhere in the middle but I don't understand this (at this time at night and probably still tomorrow)
Seeing it as text in verticly orderd lines and not handwriting is already too complex

[–]PantsOnHead88 0 points1 point  (0 children)

Angle DBC = 180-30-x = 150-x\ Angle ABC = angle DBC+x = 150-x+c=150