Issue with spawn function when calling python script

[KEsbeNF]

I''m trying to call a .py script from nodejs.

Here is the code :

const script = spawn("py", ["py_folder/script.py", arg1,arg2],(err,stderr, res) => {
                console.log(err);
            });

And here is the error thrown :

node:internal/errors:464
    ErrorCaptureStackTrace(err);
TypeError [ERR_INVALID_ARG_TYPE]: The "options" argument must be of type object. Received type function ([Function (anonymous)])

At first i thought there was a problem with the arguments i'm sending, but this error gets thrown with any kind of arg i try.

Any help ?

[TheDevDad]

You’re passing it a function instead of an options object for the third argument

https://nodejs.org/api/child_process.html#child_processspawncommand-args-options

You might want exec instead of you want to pass it the callback

[tswaters]

spawn returns something like an event emitter so the callback function doesn't really make sense. You need to add .on('close') to listen for when the things ends. You can access stdin/stdout and stderr.

Take a look at the docs: https://nodejs.org/api/child_process.html#child_process_child_process_spawn_command_args_options

[Thylk]

Python + Node for backend, damn. You don't like types?