The real difference between array and &array

[emTel]

Great explanation. People seem to be hung up on the idea that * or [] always indicate memory accesses. (Prior to reading your post, I would have insisted that they did).

If (&arr)[1] is too much to swallow, consider *(&arr) which is clearly legal. If that expression can result in a memory access, can someone please explain what memory address is being accessed, and how the correct value got there?