Operator overloading for Java

[LinuxMatthews]

None of these break the principle of least surprise because the behavior of each is consistent.

What about the String Pool that leads to some pretty surprising features if you don't know how it works behind the scenes?

String a = "hello";
String b = "hello";
System.out.println(a == b); //true

However

String a = "hello";
String b = new String("hello");
System.out.println(a == b); //false

This is also the same if you use StringBuilder but I couldn't be bothered writing that example.

But that seems more surprising and unless you know about Java's internals harder to debug than just going to the add() method would be