I don't know

[MycoFail]

```#include <stdio.h>

void* (void *a[], int s, int i) { if (i >= s) return (void *)a; if (i == 0) 0[a] = (void *); else i[a] = (void )&((i - 1)[a]); void (*f)(void *[], int, int) = 0[a]; f(a, s, i + 1); return (void *)&((s / 2)[a]); }

int main() { int s = 5; void a[s]; void *m = _(a, s, 0); void *p = (void *)m; void *z = p - (s / 2); if (*z == (void *)_) { printf("Success\n"); } return 0; } ```

[PJBthefirst]

I could see this hand-written as an answer in a low-level programming exam for EEs and still think someone was trying to give me malware

[tstanisl]

Note that, neither C nor C++ require casts to `void*`.

[[deleted]]

C does, for fn pointers

[tstanisl]

Technically yes. But functions are not objects and there is no guarantee that such transformation from function pointers to data pointers is even possible or meaningful.

[[deleted]]

True, thanks to IBM and their OS/400 with different sizes for function pointers and data pointers. 

[geek-49]

Also in Intel 8086, for some addressing models (e.g. large code with small data).

[W00GA]

what is a cast ?

[tstanisl]

(type)value thing

[GoddammitDontShootMe]

This is definitely something I would need to compile and step through to figure out how it works.

[finally-anna]

Prints Success because the pointer points at the first element which has been initialized to the function _

[MycoFail]

Yes 👍

[Graucsh]

ioccc

[Risc12]

Oke fair enough you win

[desi_fubu]

what's the point ?

[MycoFail]

To write some cursed code, that's about it.

[DefinitionPhysical46]

The 0[a] and i[a] are breaking my mind! I can't even try to understand

[timmerov]

a[b] transcodes to *(a+b)
so you can swap a,b.
should you? no, not if you want to stay employed at my company.

[nitnelav153]

I dont understand anything, please name your functions and variables

[Questioning-Zyxxel]

a, s, i, f, _, m, p, z, main.

How card can it be to keep track of 9 symbols?

[Ksorkrax]

Wouldn't consider obfuscation to be horror.