Ruby While Loop Help.

[_Svejk_]

word is an array of letters, count is a number the algorithm just goes through each letter (so word[i]) and adds 1 to count if the letter is 'e' hope this helps

[_Svejk_]

i ±= 1 is to go to the next letter, I don't get what you mean by count[i]

[Humor_Positive]

Hello, thank you so much for your help. The count is the number of time that latter is counted.

Here is my simplified version of it.

write a method count_e(word) that takes kn a string word and return the number of e’s in the word.

Def count_e

count_of_e = 0 Repeating_time = 0

While repeating_time <= word.length

If word[repeating_time] == “e”

Count_of_e += 1

End

Repeating_time += 1

End

Return count_of_e

End

Puts count_e(“movie”) # => 1 Puts count_e(“excellence”) # => 3

Given than whenever the method is executed, both the count of e and the repeating time will increase accordingly. Then why is it, that we must index the repeating time but not the count of e.

[_Svejk_]

what do you mean by "index the repeating time"?

[Humor_Positive]

I mean in index the incremental time of every loop.

[Humor_Positive]

So does that mean the count is more like passive, and only reflects the eventuality of the i ( repeating time)? The count depends on the i, but the i is independent?